10. Appendix
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Equating the two expressions for Nn/Nm one obtains now:<br />
u(Ó) Anm/{Bmn exp[(En Em)/kBT] Bnm}.<br />
Solution to Problem 7.5 649<br />
This expression becomes equal to Planck’s Radiation Law when one assumes<br />
that:<br />
Bmn Bnm and Anm<br />
Bnm<br />
Solution to Problem 7.5<br />
8applehÓ3 n 3 r<br />
c 3<br />
According to Problem 3.7 the wurtzite crystal structure possesses 4 atoms<br />
per primitive unit cell (double the number in the zincblende structure). As<br />
a result, there are 9 zone-center optical phonon modes with symmetries:<br />
°1 ⊕2°3 ⊕°5 ⊕2°6 (or A1 ⊕2B1 ⊕E1 ⊕2E2 using the C6v point group notation).<br />
One should note that the E modes are doubly degenerate and not all of these<br />
optical phonons are Raman-active.<br />
To determine the symmetry of the Raman-active phonon modes we note<br />
that, unlike absorption, Raman scattering involves two electromagnetic (EM)<br />
waves: one incident and one scattered wave. If we want to annihilate a photon<br />
and generate a phonon, as in optical absorption, then the phonon must<br />
have the same symmetry as the photon (which belongs to the same representation<br />
as a vector). We have already obtained this result as one of the many<br />
applications of group theory (see Section 2.3.4). In Raman scattering we annihilate<br />
the incident photon and create a scattered photon with the generation<br />
or annihilation of a phonon. The symmetry of the phonons involved is going<br />
to be the same as in the case where two photons are annihilated to generate<br />
one phonon (i.e. a two-photon absorption process). The reason is that the matrix<br />
elements describing the photon creation and annihilation processes are the<br />
same except for a term involving the photon occupancy factor Np (see Section<br />
7.1). Thus the representation of the phonon (or phonons) involved in Raman<br />
scattering must be contained within the direct product of the representations of<br />
two vectors.<br />
For example, a vector in zincblende-type crystals belongs to the °4 irreducible<br />
representation. Thus the representation of the Raman-active phonons<br />
must belong to the direct product:<br />
°4 ⊗ °4 °1 ⊕ °2 ⊕ °4.<br />
Although the zone-center optical phonons in zincblende-type crystals have °4<br />
symmetry, Raman scattering from phonon modes with the °1 and °2 symmetry<br />
can also be observed in the two-phonon spectra of zincblende-type crystals.<br />
See, for example, Fig. 7.22 for the various symmetry components of the twophonon<br />
Raman spectra of Si.