27.04.2013 Views

10. Appendix

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Equating the two expressions for Nn/Nm one obtains now:<br />

u(Ó) Anm/{Bmn exp[(En Em)/kBT] Bnm}.<br />

Solution to Problem 7.5 649<br />

This expression becomes equal to Planck’s Radiation Law when one assumes<br />

that:<br />

Bmn Bnm and Anm<br />

Bnm<br />

Solution to Problem 7.5<br />

8applehÓ3 n 3 r<br />

c 3<br />

According to Problem 3.7 the wurtzite crystal structure possesses 4 atoms<br />

per primitive unit cell (double the number in the zincblende structure). As<br />

a result, there are 9 zone-center optical phonon modes with symmetries:<br />

°1 ⊕2°3 ⊕°5 ⊕2°6 (or A1 ⊕2B1 ⊕E1 ⊕2E2 using the C6v point group notation).<br />

One should note that the E modes are doubly degenerate and not all of these<br />

optical phonons are Raman-active.<br />

To determine the symmetry of the Raman-active phonon modes we note<br />

that, unlike absorption, Raman scattering involves two electromagnetic (EM)<br />

waves: one incident and one scattered wave. If we want to annihilate a photon<br />

and generate a phonon, as in optical absorption, then the phonon must<br />

have the same symmetry as the photon (which belongs to the same representation<br />

as a vector). We have already obtained this result as one of the many<br />

applications of group theory (see Section 2.3.4). In Raman scattering we annihilate<br />

the incident photon and create a scattered photon with the generation<br />

or annihilation of a phonon. The symmetry of the phonons involved is going<br />

to be the same as in the case where two photons are annihilated to generate<br />

one phonon (i.e. a two-photon absorption process). The reason is that the matrix<br />

elements describing the photon creation and annihilation processes are the<br />

same except for a term involving the photon occupancy factor Np (see Section<br />

7.1). Thus the representation of the phonon (or phonons) involved in Raman<br />

scattering must be contained within the direct product of the representations of<br />

two vectors.<br />

For example, a vector in zincblende-type crystals belongs to the °4 irreducible<br />

representation. Thus the representation of the Raman-active phonons<br />

must belong to the direct product:<br />

°4 ⊗ °4 °1 ⊕ °2 ⊕ °4.<br />

Although the zone-center optical phonons in zincblende-type crystals have °4<br />

symmetry, Raman scattering from phonon modes with the °1 and °2 symmetry<br />

can also be observed in the two-phonon spectra of zincblende-type crystals.<br />

See, for example, Fig. 7.22 for the various symmetry components of the twophonon<br />

Raman spectra of Si.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!