10. Appendix
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650 <strong>Appendix</strong> B<br />
To determine the symmetry of the Raman-active phonons in wurtzite crystals,<br />
we need to determine the irreducible representations of a vector in the<br />
wurtzite structure. From Problem 3.7 we find that the character table for the<br />
wurtzite structure becomes identical to that of point group C6v in the limit<br />
when the phonon wave vector approaches zero. Assuming that one chooses<br />
the z-axis to be parallel to the C6 axis of this point group or the c-axis of the<br />
wurtzite structure (this axis will also be labeled as 3 in subsequent tensor subscripts,<br />
while the x and y axes will be labeled as 1 and 2, respectively). Since<br />
the largest dimension of irreducible representations in C6v is 2, the representation<br />
of a vector in 3D (with components x, y and z) has to be reducible. One<br />
way this representation can be reduced is to separate {z} from {x, y}. {z}<br />
must belong to the A1 irreducible representation since it is invariant under all<br />
the symmetry operations of C6v. The remaining components {x} and {y} form<br />
a 2D irreducible representation. Whether this irreducible representation is of<br />
symmetry E1 or E2 can be decided by applying to {x, y} the C2 operation (a<br />
rotation by 180 ◦ about the z-axis): xy → xy. The character for this operation<br />
is 2. Hence {x, y} belongs to the E1 irreducible representation. The above<br />
result can be summarized as: the irreducible representations to which a vector<br />
in the group C6v belongs are A1 and E1.<br />
Based on this result we can predict that the zone-center phonons of symmetry<br />
°1 and °5 in the wurtzite crystal (corresponding to A1 and E1 representations,<br />
respectively, in C6v) are infrared-active. To obtain the symmetry of the<br />
corresponding Raman active phonons we have to calculate the direct product:<br />
(A1 ⊕ E1) ⊗ (A1 ⊕ E1). By inspection of the character table of C6v in Problem<br />
3.7 it can be shown that: E1 ⊗ E1 A1 ⊕ A2 ⊕ E2. Thus one obtains the result:<br />
(A1 ⊕ E1) ⊗ (A1 ⊕ E1) 2A1 ⊕ A2 ⊕ 2E1 ⊕ E2.<br />
In summary, in systems with C6v point group symmetry the Raman-active<br />
phonon modes must belong to the A1, A2, E1 or E2 irreducible representations.<br />
Similarly, the Raman-active zone-center optical phonons in the wurtzite<br />
crystal structure must belong to the °1, °2, °5, or°6 irreducible representations.<br />
Thus, of all the 9 zone-center optical phonons in the wurtzite structure the<br />
ones with °1 and °5 symmetries are both infrared and Raman active; the two<br />
phonons with °6 symmetry are only Raman-active while the two phonons with<br />
°3 symmetry are neither infrared nor Raman active (such modes are said to<br />
be silent).<br />
To obtain the Raman tensor for the Raman-active phonons we have to<br />
derive, in principle, the form of the phonon displacement vector Qk and the<br />
electric susceptibility tensor ¯ and then apply Eq. (7.37) to obtain the Raman<br />
tensor Rij. In reality, we can choose any basis function in lieu of the phonon<br />
displacement vectors, provided they belong to the same irreducible representation.<br />
As, an example, let us consider the °1 optical phonon. As shown in Problem<br />
3.15 the third order electromechanical tensor (em) in the wurtzite crystal<br />
has only three linearly-independent and non-zero elements: (em)15, (em)31,<br />
and (em)33. Since the third rank tensor (¯/Q) has the same symmetry prop-