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10. Appendix

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646 <strong>Appendix</strong> B<br />

electron is close to the core where V is large the electron wave function ˇ<br />

will be varying rapidly over a distance which is of the order of the Bohr radius.<br />

On the other hand, (1/k) is of the order of the lattice constant which is<br />

much larger than the Bohr radius. Therefore 〈ˇ|p|ˇ〉 ∼〈ˇ|∇|ˇ〉 tends to be<br />

much larger than k (see, for example, E.O. Kane: Energy band structure in<br />

p-type germanium and silicon. J. Phys. Chem. Solids 1, 83 (1956)). When the<br />

second term is neglected we obtain again (2.45a) for the S-O coupling. However,<br />

for a general point k in the Brillouin Zone one finds the k · p term to be<br />

the dominant interaction which mixes the k 0 electron states so the effect<br />

of HSO on the electrons is no longer discernible. There are two exceptional<br />

cases though. They are when k is along the [111] or [100] directions.<br />

In Sections 2.4.1 and 2.4.2 we learn that the group of § in both the<br />

zincblende and diamond structure has three-fold rotational symmetry about<br />

the [111] axis. This symmetry is high enough that in the diamond-type semiconductor<br />

the triply degenerate p-like wave functions at k 0 splits into a<br />

doublet with symmetry §3 and a singlet with symmetry §1. See Fig. 2.10 for<br />

the band structure in Si neglecting S-O splitting and Table 2.12 for the character<br />

table (same for diamond and zincblende crystals along the [111] direction<br />

as long as k is inside the Brillouin zone). This degeneracy of the §3 state can<br />

be split by the S-O coupling.<br />

In fact, we can model the valence band electron in this case as a “p-like”<br />

electron in a cylindrical potential. In case of the L 1 state we expect the<br />

three degenerate states to be split into a doublet with Lz ±1 and a singlet<br />

with Lz 0 We will assume that the axis of quantization of the angular<br />

momentum vector L to be the [111] axis which will be labeled as the z-axis<br />

to simplify the notation. We can identify the doubly degenerate §3 states as<br />

corresponding to the Lz ±1 states. The wave functions for the §3 state can<br />

then be represented as [|X〉 i|Y〉]/ √ 2 and [|X〉 i|Y〉]/ √ 2 to correspond to<br />

the Lz ±1 states. Again |X〉 and |Y〉 are shorthand notations for the two §3<br />

wave functions which transform into each under the symmetry operations of<br />

the group of § like the spatial coordinates x and y. In this coordinate system<br />

the S-O interaction is given by: HSO Ï ′ L · S Ï ′ LzSz. We will assume at<br />

first that the spin-orbit coupling constant Ï ′ is not the same as Ï. We can show<br />

that:<br />

〈Lz 1, Sz 1/2|HSO|Lz 1, Sz 1/2〉 Ï ′ /2 while<br />

〈Lz 1, Sz 1/2|HSO|Lz 1, Sz 1/2〉 Ï ′ /2.<br />

Similarly 〈Lz 1, Sz 1/2|HSO|Lz 1, Sz 1/2〉 Ï ′ /2 while<br />

〈Lz 1, Sz 1/2|HSO|Lz 1, Sz 1/2〉 Ï ′ /2.<br />

In other words, along the [111] direction the Jz ±3/2 states are split<br />

from the Jz ±1/2 states by the spin-orbit coupling. The magnitude of the<br />

S-O coupling ¢1 is equal to Ï ′ .IfÏ Ï ′ then we obtain the “two-thirds rule”:<br />

¢1/¢0 2/3.<br />

The reason why one may expect Ï to differ from Ï ′ is that the k · p perturbation<br />

term mixes the k 0 wave functions. For example, the k · p term<br />

will mix the anti-bonding °15 conduction band wave function with the bonding

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