10. Appendix
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Solution to Problem 6.21 645<br />
by a simple constant Í. The valence electron wave functions in an atom are<br />
normalized to the total number of valence electrons/atom over the entire<br />
space. However, the valence band wave functions in a crystal are normalized<br />
over a unit cell by the total number of valence electrons/unit cell. Thus,<br />
the probability of finding a valence electron near the atomic nuclei will be<br />
enhanced in the crystal leading to a stronger S-O coupling. In other words:<br />
¢crystal Í¢atom with Í 1. As an example, ¢atom 0.219 eV for the 4p<br />
electrons in Ge (see, for example, the Atomic Spectra Database at the NIST<br />
website: http://physics.nist.gov/PhysRefData/ASD/index.html). The corresponding<br />
¢0 for the p-like top valence band at k 0 in Ge crystal is 0.296 eV. Thus,<br />
the enhancement factor Í is about 1.4, which is quite substantial.<br />
For a binary compound semiconductor, like GaAs, we expect that that<br />
S-O coupling for the valence electrons will depend on the S-O coupling of<br />
the outermost filled core electrons in both the cation and the anion. A simple<br />
approach would be to assume that ¢crystal Í1¢atom1 Í2¢atom2. If the electron<br />
spends equal time around the cation and the anion one would expect the<br />
ratio Í1/Í2 1. In ionic compounds this is usually not the case. For example,<br />
in GaAs the valence electrons spend more time around the As atoms so one<br />
expects that ÍAs/ÍGa 1. Indeed a ratio of ÍV/ÍIII 1.86 has been suggested<br />
for III-V compounds. An even larger ratio is expected for the II-VI semiconductors.<br />
So far we have been considering the effect of HS-O on the degenerate plike<br />
valence band states at the zone center. When the electron wave vector k<br />
increases from the zone center along a general direction, one would not expect<br />
the above model based on a spherical potential to be valid. Hence one<br />
may not be able to predict the contribution of HS-O to the band splitting. Using<br />
the k · p approach, the orbital part of the Hamiltonian of the electron as<br />
given by (2.35) is:<br />
H H0 [(k) 2 /2m] (/m)k · p<br />
Where H0 is the Hamiltonian for k 0. The k · p term now appears as an<br />
additional contribution to the crystal potential term and as a result HSO becomes<br />
k dependent. Instead of changing the crystal potential in response to<br />
the non-zero value of k we can interpret this effect as the electron now moving<br />
with velocity v k/m. We will choose a moving coordinate system O ′<br />
which is traveling with the electron (the electron rest frame). In this moving<br />
frame O ′ the spin-orbit Hamiltonian is again given by: HSO(v 0) <br />
[(/4c2m2 ][(∇V × p) · Û]. However, the electron momentum p ′ in the stationary<br />
(or laboratory frame) O is now given by p ′ p k. Thus the spin-orbit<br />
Hamiltonian in the frame O is:<br />
HSO(k) [h/4c 2 m 2 ][(∇V × p ′ ) · Û]<br />
[/4c 2 m 2 ][(∇V × p) · Û (∇V × k) · Û]<br />
In this Hamiltonian V and p both refer to the electron rest frame and, therefore,<br />
are calculated just as for the zone center electrons. In general, the second<br />
term is much smaller than the first one. The reasoning is like this: when the