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10. Appendix

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Solution to Problem 6.7 633<br />

axes. For E E0 the constant energy curve is shown schematically in the<br />

following figure.<br />

k 2<br />

2 2 1/2<br />

2 k 1 2<br />

1<br />

k 1<br />

2 2<br />

E=E o+k 1– k 2<br />

The DOS is proportional to:<br />

<br />

dSk<br />

|∇kE| <br />

<br />

kB (dk1)<br />

0<br />

2 (dk2) 2<br />

<br />

k2 1 k2 2<br />

Using the result that:<br />

<br />

dx<br />

√<br />

x2 a2 log <br />

e x √ x2 a2 <br />

<br />

k2 B (E E0)<br />

<br />

kB<br />

0<br />

dk2<br />

|k1| <br />

kB<br />

0<br />

dk2<br />

<br />

k2 2 (E E0)<br />

We obtain the DOS as proportional to:<br />

<br />

<br />

<br />

loge kB <br />

loge E E0 ∼ C loge E E0<br />

The dependence on E of the first term in the above expression can be neglected<br />

since k 2 B ≫ (EE0). As a result, it can be approximated by a constant<br />

C. The dependence of the DOS is, therefore, determined by the second term<br />

which diverges logarithmically at E E0.<br />

The results we have obtained in this problem show that the energy dependence<br />

of the DOS is strongly dependent on the functional relation between<br />

the energy E and the wave vector k which, in turn, depends strongly on the<br />

dimensionality of the k-space and real space under consideration.<br />

Solution to Problem 6.7<br />

(c) A good starting point to solve this problem would be [6.44], the classic paper<br />

by R.J. Elliott, on the intensity of optical absorption by excitons. For direct<br />

excitons the transition probability per unit time (P) for an incident radiation

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