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Radar System Engineering

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SEC. 10.7] PULSER CIRCUITS 359<br />

tude of the first reflection would be only 7 per cent of that of the main<br />

pulse, and the power involved in that reflection is only 0.5 per cent of that<br />

of the main pulse. Forall practical designs, a mismatch of 20t030 per<br />

cent is acceptable from the standpoint of energy loss. Design considerations<br />

for the best use of available components usually make it preferable<br />

to keep the impedance 20 small, generally about 50 ohms. The load<br />

resistances encountered in practice are approximately 500 ohms or higher.<br />

In such a case, the load and the line are matched through a pulse transformer.<br />

The voltage step-up ratio of the pulse transformer, n, is chosen<br />

to make n2 = RL/Zo.<br />

If R. = Zo, it can be shown easily that all the energy stored in the<br />

transmission line is dissipated in the load. Again, from elementary<br />

theory,<br />

Z, = ~L/C = -;<br />

6=lm=m0,<br />

where 1 is the length of the line, L and C its inductance and capacity per<br />

unit length, Lo = lL the total inductance of the line, and Co = lC its total<br />

capacity. The energy stored is given by<br />

but<br />

w<br />

= + Cov:,<br />

On the other hand, the energy dissipated in the load is given by<br />

or, since<br />

v;<br />

‘0 = FL ‘0’<br />

v.=: and R= = 20,<br />

w, = ~go to = w;<br />

therefore all the energy stored in the line is dissipated in the load.<br />

This method thus provides a very efficient way of obtaining a rectangular<br />

pulse of energy in a resistance load. It is usually impractical to use<br />

actual transmission lines or cables in actual pulsers; a cable to supply a<br />

l-psec pulse would be approximately 500 ft long. This difficulty can be<br />

easily circumvented by the use of artificial transmission lines or of a pulsefdrming<br />

network.

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