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handbook of modern sensors

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5.9 Noise in Sensors and Circuits 213<br />

capacitance can be modeled by circuit shown in Fig. 5.48. Here, e n is a noise source.<br />

It may be some kind <strong>of</strong> a part or component whose electric potential varies. C s is the<br />

stray capacitance (having impedance Z s at a particular frequency) between the noise<br />

source and the circuit impedance Z, which acts as a receiver <strong>of</strong> the noise. The voltage<br />

V n is a result <strong>of</strong> the capacitive coupling. A noise current is defined as<br />

and actually produces noise voltage<br />

i n =<br />

V n =<br />

V n<br />

Z + Z s<br />

(5.83)<br />

e n<br />

1 + Z c /Z . (5.84)<br />

For example, if C s = 2.5 pF,Z = 10 k (resistor), and e n = 100 mV, at 1.3MHz the<br />

output noise will be 20 mV.<br />

One might think that 1.3-MHz noise is relatively easy to filter out from lowfrequency<br />

signals produced by a sensor. In reality, it cannot be done, because many<br />

<strong>sensors</strong> and, especially the front stages <strong>of</strong> the amplifiers, contain nonlinear components<br />

(p-n-semiconductor junctions) which act as rectifiers. As a result, the spectrum<br />

<strong>of</strong> high-frequency noise shifts into a low-frequency region, making the noise signal<br />

similar to the voltage produced by a sensor.<br />

When a shield is added, the change to the situation is shown in Fig. 5.48B. With<br />

the assumption that the shield has zero impedance, the noise current at the left side will<br />

be i n1 = e n /Z C1 . On the other side <strong>of</strong> the shield, noise current will be essentially zero<br />

because there is no driving source on the right side <strong>of</strong> the circuit. Subsequently, the<br />

noise voltage over the receiving impedance will also be zero and the sensitive circuit<br />

becomes effectively shielded from the noise source. One must be careful, however,<br />

that there is no currents is flowing over the shield. Coupled with the shield resistance,<br />

these may generate additional noise. There are several practical rules that must be<br />

observed when applying electrostatic shields:<br />

• An electrostatic shield, to be effective, should be connected to the reference potential<br />

<strong>of</strong> any circuitry contained within the shield. If the signal is connected to<br />

a ground (chassis <strong>of</strong> the frame or to earth), the shield must be connected to that<br />

ground. Grounding <strong>of</strong> shield is useless if the signal is not returned to the ground.<br />

• If a shielding cable is used, its shield must be connected to the signal referenced<br />

node at the signal source side (Fig. 5.49A).<br />

• If the shield is split into sections, as might occur if connectors are used, the shield<br />

for each segment must be tied to those for the adjoining segments and ultimately<br />

connected only to the signal referenced node (Fig. 5.49B).<br />

• The number <strong>of</strong> separate shields required in a data acquisition system is equal to the<br />

number <strong>of</strong> independent signals that are being measured. Each signal should have<br />

its own shield, with no connection to other shields in the system, unless they share<br />

a common reference potential (signal “ground”). In that case, all connections must<br />

be made by a separate jumping wire connected to each shield at a single point.<br />

• A shield must be grounded only at one point—preferably next to the sensor. A<br />

shielded cable must never be grounded at both ends (Fig. 5.50). The potential

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