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Educability-and-Group-Differences-1973-by-Arthur-Robert-Jensen

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Race <strong>Differences</strong> in Intelligence 195<br />

NOTES<br />

1. A critique of the SPSSI Council’s statement was published <strong>by</strong><br />

<strong>Jensen</strong> (1969c).<br />

2. Obtained scores can be conceived of as analyzable into two components:<br />

true-scores plus an error component. The reliability (rtt)<br />

of a test is defined as the ratio of true score variance to obtained<br />

score variance <strong>and</strong> the proportion of variance due to measurement<br />

error, therefore, is 1 —rtt. Errors of measurement, being r<strong>and</strong>om,<br />

cancel each other when scores are averaged to obtain a group mean.<br />

Adding a r<strong>and</strong>om number (half of which are + <strong>and</strong> half —) to<br />

each score in a distribution, where the number of scores is large,<br />

will increase the variance of the distribution but will not significantly<br />

alter the mean. On the other h<strong>and</strong>, when the absolute difference<br />

(i.e., a difference regardless of its sign, + or —) between a pair<br />

of scores is obtained, it includes the measurement error. For<br />

example, imagine a set of many pairs of ‘true’ scores (i.e., scores<br />

without any error) in which the scores of both members of each<br />

pair are identical (although the mean of each pair may differ from<br />

the mean of every other pair). The mean of the absolute differences<br />

within pairs, therefore, will be zero. Now imagine adding r<strong>and</strong>om<br />

numbers (i.e., error) to every individual score. Then the mean of<br />

the absolute differences within pairs will be some value greater<br />

than zero. This value constitutes measurement error.<br />

3. The correlation between twins can be determined from the mean<br />

absolute difference |d \ between twin pairs from the following<br />

formula<br />

where<br />

\dk\ — mean absolute difference between kinship members,<br />

|dp\ = mean absolute difference between all possible paired<br />

comparisons in the general population, <strong>and</strong><br />

\ir\<br />

M3«r<br />

Since the population o for IQ is 15, <strong>and</strong> the twin difference is 6-60,<br />

the above formula yields a value for r = 0-85. Thus, if the genetic<br />

variance for IQ = 0-85 x 152 = 191-25, <strong>and</strong> the error variance is<br />

(1—r t)er2 [where rn is test reliability] = (—1-95)152 = 11-25, <strong>and</strong><br />

the total variance is 152 = 225, then the environmental variance<br />

(i.e., the remainder) must equal 22-50, which has a st<strong>and</strong>ard

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