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Pile Design and Construction Practice, Fifth edition

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214 Resistance of piles to compressive loads<br />

or rock. No support for compressive loads from shaft friction can be assumed over the length<br />

of the pile shaft through the fill. This is because of the downward movement of the fill as it<br />

compresses under its own weight or under the weight of further soil or surcharge placed over<br />

the fill area. The downward movement results in drag-down forces, generally known as<br />

negative skin friction, on the pile shaft. Where fill is placed over a compressible natural soil<br />

the latter consolidates <strong>and</strong> moves downwards relative to the pile. Thus the negative skin<br />

friction occurs over the length of the shaft within the natural soil as well as within the fill.<br />

Calculation of the magnitude of the negative skin friction is a complex problem which<br />

depends on the following factors:<br />

(1) The relative movement between the fill <strong>and</strong> the pile shaft<br />

(2) The relative movement between any underlying compressible soil <strong>and</strong> the pile shaft<br />

(3) The elastic compression of the pile under the working load <strong>and</strong><br />

(4) The rate of consolidation of the compressible layers.<br />

The simplest case is fill that is placed over a relatively incompressible rock with piles<br />

driven to refusal in the rock. The toe of the pile does not yield under the combined working<br />

load <strong>and</strong> drag-down forces. Thus the negative skin friction on the upper part of the pile<br />

shaft is equal to the fully mobilized value. Near the base of the fill its downward movement<br />

may be insufficiently large to mobilize the full skin friction, <strong>and</strong> immediately above rockhead<br />

the fill will not settle at all relative to the pile shaft. Thus negative skin friction cannot<br />

occur at this point. The distribution of negative skin friction on the shaft of the unloaded<br />

pile is shown in Figure 4.38a. If a heavy working load is now applied to the pile shaft, the<br />

shaft compresses elastically <strong>and</strong> the head of the pile moves downwards relative to the fill.<br />

The upper part of the fill now acts in support of the pile although this contribution is<br />

neglected in calculating the pile resistance. The distribution of negative skin friction on the<br />

shaft of the loaded pile is shown in Figure 4.38b. Where the fill has been placed at a<br />

relatively short period of time before installing the piles, continuing consolidation of the<br />

material will again cause it to slip downwards relative to the pile shaft, thus re-activating<br />

the drag-down force.<br />

The simplified profile of negative skin friction for a loaded pile on an incompressible<br />

stratum is shown in Figure 4.38c. This diagram can be used to calculate the magnitude of<br />

the drag-down forces. The peak values for coarse soils <strong>and</strong> fill material are calculated by the<br />

method described in Section 4.3.<br />

In the case where negative skin friction is developed in clays, the rate of loading must be<br />

considered. It was noted in Section 4.2.4 that the capacity of a clay to support a pile in skin<br />

friction is substantially reduced if the load is applied to the pile at a very slow rate. The same<br />

consideration applies to negative skin friction, but in this case it works advantageously in<br />

reducing the magnitude of the drag-down force. In most cases of negative skin friction in<br />

clays the relative movement between the soil which causes drag-down <strong>and</strong> the pile takes<br />

place at a very slow rate. The movement is due to the consolidation of the clay under its own<br />

weight or under imposed loading, <strong>and</strong> this process is very slow compared with the rate of<br />

application of the working load to the pile.<br />

Meyerhof (4.37) advises that the negative skin friction on piles driven into soft to firm clays<br />

should be calculated in terms of effective stress from the equation:<br />

� s neg � ��� vo<br />

(4.50)

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