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Agilent Spectrum Analysis Basics - Agilent Technologies

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To separate closely spaced signals (see “Resolving signals” later in this<br />

chapter), some spectrum analyzers have IF bandwidths as narrow as 1 kHz;<br />

others, 10 Hz; still others, 1 Hz. Such narrow filters are difficult to achieve<br />

at a center frequency of 3.9 GHz. So we must add additional mixing stages,<br />

typically two to four stages, to down-convert from the first to the final IF.<br />

Figure 2-5 shows a possible IF chain based on the architecture of a typical<br />

spectrum analyzer. The full tuning equation for this analyzer is:<br />

However,<br />

f sig = f LO1 – (f LO2 + f LO3 + f final IF )<br />

f LO2 + f LO3 + f final IF<br />

= 3.6 GHz + 300 MHz + 21.4 MHz<br />

= 3.9214 GHz, the first IF<br />

3 GHz<br />

3.9214 GHz 321.4 MHz<br />

21.4 MHz Envelope<br />

detector<br />

3.9 - 7.0 GHz<br />

3.6 GHz<br />

300 MHz<br />

Sweep<br />

generator<br />

Display<br />

Figure 2-5. Most spectrum analyzers use two to four mixing steps to reach the final IF<br />

So simplifying the tuning equation by using just the first IF leads us to the<br />

same answers. Although only passive filters are shown in the diagram, the<br />

actual implementation includes amplification in the narrower IF stages.<br />

The final IF section contains additional components, such as logarithmic<br />

amplifiers or analog to digital converters, depending on the design of the<br />

particular analyzer.<br />

Most RF spectrum analyzers allow an LO frequency as low as, and even below,<br />

the first IF. Because there is finite isolation between the LO and IF ports of<br />

the mixer, the LO appears at the mixer output. When the LO equals the IF,<br />

the LO signal itself is processed by the system and appears as a response<br />

on the display, as if it were an input signal at 0 Hz. This response, called LO<br />

feedthrough, can mask very low frequency signals, so not all analyzers allow<br />

the display range to include 0 Hz.<br />

15

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