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Agilent Spectrum Analysis Basics - Agilent Technologies

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Next let’s see to what extent harmonic mixing complicates the situation.<br />

Harmonic mixing comes about because the LO provides a high-level drive<br />

signal to the mixer for efficient mixing, and since the mixer is a non-linear<br />

device, it generates harmonics of the LO signal. Incoming signals can mix<br />

against LO harmonics, just as well as the fundamental, and any mixing<br />

product that equals the IF produces a response on the display. In other words,<br />

our tuning (mixing) equation now becomes:<br />

f sig = nf LO ±f IF<br />

where<br />

n = LO harmonic<br />

(Other parameters remain the same as previously discussed)<br />

Let’s add second-harmonic mixing to our graph in Figure 7-3 and see to what<br />

extent this complicates our measurement procedure. As before, we shall first<br />

plot the LO frequency against the signal frequency axis. Multiplying the<br />

LO frequency by two yields the upper dashed line of Figure 7-3. As we did<br />

for fundamental mixing, we simply subtract the IF (3.9 GHz) from and add<br />

it to the LO second-harmonic curve to produce the 2 – and 2 + tuning ranges.<br />

Since neither of these overlap the desired 1 – tuning range, we can again argue<br />

that they do not really complicate the measurement process. In other words,<br />

signals in the 1 – tuning range produce unique, unambiguous responses on<br />

our analyzer display. The same low-pass filter used in the fundamental mixing<br />

case works equally well for eliminating responses created in the harmonic<br />

mixing case.<br />

2+<br />

15<br />

2xLO<br />

Signal frequency (GHz)<br />

10<br />

5<br />

1+<br />

2–<br />

LO<br />

1–<br />

0<br />

4 5 6<br />

LO frequency (GHz)<br />

7<br />

Figure 7-3. Signals in the “1 minus” frequency range produce<br />

single, unambiguous responses in the low band, high IF case<br />

85

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