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Agilent Spectrum Analysis Basics - Agilent Technologies

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On the other hand, the rise time of a filter is inversely proportional to its<br />

bandwidth, and if we include a constant of proportionality, k, then:<br />

Rise time =<br />

k<br />

RBW<br />

If we make the terms equal and solve for sweep time, we have:<br />

k<br />

RBW<br />

ST =<br />

= (RBW)(ST) or:<br />

Span<br />

k (Span)<br />

RBW 2<br />

The value of k is in the 2 to 3 range for the synchronously-tuned,<br />

near-Gaussian filters used in many <strong>Agilent</strong> analyzers.<br />

The important message here is that a change in resolution has a dramatic<br />

effect on sweep time. Most <strong>Agilent</strong> analyzers provide values in a 1, 3, 10<br />

sequence or in ratios roughly equaling the square root of 10. So sweep time<br />

is affected by a factor of about 10 with each step in resolution. <strong>Agilent</strong> PSA<br />

Series spectrum analyzers offer bandwidth steps of just 10% for an even<br />

better compromise among span, resolution, and sweep time.<br />

<strong>Spectrum</strong> analyzers automatically couple sweep time to the span and<br />

resolution bandwidth settings. Sweep time is adjusted to maintain a calibrated<br />

display. If a sweep time longer than the maximum available is called for,<br />

the analyzer indicates that the display is uncalibrated with a “Meas Uncal”<br />

message in the upper-right part of the graticule. We are allowed to override<br />

the automatic setting and set sweep time manually if the need arises.<br />

Digital resolution filters<br />

The digital resolution filters used in <strong>Agilent</strong> spectrum analyzers have an<br />

effect on sweep time that is different from the effects we’ve just discussed for<br />

analog filters. For swept analysis, the speed of digitally implemented filters<br />

can show a 2 to 4 times improvement. FFT-based digital filters show an even<br />

greater difference. This difference occurs because the signal being analyzed<br />

is processed in frequency blocks, depending upon the particular analyzer.<br />

For example, if the frequency block was 1 kHz, then when we select a 10 Hz<br />

resolution bandwidth, the analyzer is in effect simultaneously processing the<br />

data in each 1 kHz block through 100 contiguous 10 Hz filters. If the digital<br />

processing were instantaneous, we would expect sweep time to be reduced<br />

by a factor of 100. In practice, the reduction factor is less, but is still<br />

significant. For more information on the advantages of digital processing,<br />

refer to Chapter 3.<br />

23

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