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UNDERSTANDING a-Si pin CELLS 529<br />

p<br />

i<br />

n<br />

1.5<br />

Near-dark<br />

1.0<br />

0.5<br />

eV BI<br />

E C<br />

0.0<br />

E F<br />

−0.5<br />

hν<br />

Level position<br />

[eV]<br />

−1.0<br />

−1.5<br />

0.5<br />

W<br />

E V<br />

E C<br />

Illuminated<br />

0.0<br />

E Fe<br />

−0.5<br />

−1.0<br />

E Fh<br />

−1.5<br />

E V<br />

0 100 200 300 400 500<br />

Position<br />

[nm]<br />

Figure 12.14 Bandedge and Fermi-level profiles in a pin solar cell under open-circuit conditions.<br />

The open-circuit voltage is precisely the value of E Fh at the left interface (x = 0). The built-in<br />

potential V BI is illustrated. Note that the p-layer has a slightly (0.2 eV) larger band gap than the<br />

i-layer; the calculation assumes symmetrical offsets of the valence and conduction bands at the<br />

p/i interface<br />

for an a-Si:H-based pin solar cell in the dark and under illumination. The figure is based<br />

on calculations using the AMPS-1D © computer program [122, 123] and an idealized set<br />

of parameters to describe a-Si:H [124]. 6 The electric field F(x) within the device causes<br />

all electron level energies such as E C and E V to vary in space in the same way; for E C<br />

the expression is eF(x) = ∂E C (x)/∂x.<br />

Where do these built-in electric fields come from? In isolation, p-type and n-<br />

type materials have very different Fermi energies; in the calculation of Figure 12.14, we<br />

assumed that E F was 1.7 eV below E C for the p-layer and was 0.05 eV below E C for<br />

the n-layer. When the pin device is assembled, these Fermi energies must be equalized to<br />

create thermal equilibrium. Electrons are donated from the n-layer to the p-layer, which<br />

generates a built-in electric field; while the level positions such as E C and E V now vary<br />

6 Many computer modeling codes have been developed; Schropp and Zeman give a good overview in Section 6.1<br />

of their monograph [123].

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