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5-Endless Bliss Fifth Fascicle - Hakikat Kitabevi

5-Endless Bliss Fifth Fascicle - Hakikat Kitabevi

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the matter is based on twenty-four. For example, when there is<br />

a wife, two daughters, a mother, and a paternal uncle, the<br />

problem is based on twenty-four, and a wife is given [24x1/8=3]<br />

three shares, the two daughters are given [24x2/3=16] sixteen<br />

shares, a mother is given four shares, and the remaining one<br />

share is given to the paternal uncle.<br />

A second example: When there is a wife, a daughter, son’s<br />

daughter, a mother, and a sister, three of the twenty-four shares<br />

are given to the wife, four shares to the son’s daughter, four<br />

shares to the mother, twelve shares to the daughter, and the<br />

remaining one share to the sister, who is an asaba.<br />

4 - When one share cannot be divided by the number of the<br />

people (who are to share it), the basis of the problem is<br />

multiplied by the number of those people, and the inheritance is<br />

divided by this new basis.<br />

For example, when there is a husband and five sisters, the<br />

basis of the problem, which is six, makes awl, [that is, changes],<br />

to seven and the five sisters get four shares. Since four shares<br />

cannot be divided by five, the number of sisters, the basis of the<br />

problem becomes 5x7=35. So, [4x5=20] twenty shares are<br />

given to the five sisters, and [3x5=15] fifteen shares to the<br />

husband.<br />

5 - If a few shares cannot be divided between the owners of<br />

those shares, the least common multiple of the number of the<br />

owners of those shares is multiplied by the basis of the problem<br />

and thus the new basis is found. The inheritance is divided by<br />

that new basis.<br />

For example, when there are three daughters and three<br />

paternal uncles, the problem is based on three and the<br />

daughters get two shares and the uncles get one; yet because<br />

the share cannot be divided by the number of individuals the<br />

basis of the problem becomes [3x3=9] nine; [9x2/3=6] six<br />

shares are given to the daughters and [9x1/3=3] three shares to<br />

the uncles.<br />

A second example: When there are two wives, ten<br />

daughters, six grandmothers and seven paternal uncles, the<br />

problem is based on twenty-four, and three shares belong to<br />

the wives, sixteen shares to the daughters, four shares to the<br />

grandmothers, and the remaining one share belongs to the<br />

uncles; but because the number of shares is not divisible by the<br />

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