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Design and Simulation of Two Stroke Engines

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<strong>Design</strong> <strong>and</strong> <strong>Simulation</strong> <strong>of</strong> <strong>Two</strong>-<strong>Stroke</strong> <strong>Engines</strong><br />

As the mass flow is found from:<br />

ms = psAcs = G5as(X! - X2)Ap0X G5<br />

s<br />

the transmitted pressure amplitude ratios, X\f <strong>and</strong> X2f, <strong>and</strong> superposition particle velocity,<br />

csf, are related by:<br />

x sf = ( x lf + x 2f " 1) <strong>and</strong> c sf = G 5 a o( x lf " x 2f)<br />

The momentum <strong>and</strong> continuity equations become two simultaneous equations for the two<br />

unknown quantities, Xif <strong>and</strong> X2f, which are found by determining csf,<br />

?sf = cs + Psf " Ps (2.3.5)<br />

Ps c s<br />

i + xsf+- c ^<br />

whence x G 5 a Q (2.3.6)<br />

"If<br />

<strong>and</strong> X2f=l+Xsf-Xif (2-3.7)<br />

Consequently the pressures <strong>of</strong> the ongoing pressure waves pif <strong>and</strong> p2f after friction has<br />

been taken into account, are determined by:<br />

Plf = Po x Pf ? <strong>and</strong> P2f = Po x 2f ? < 2 - 3 - 8 )<br />

Taking the data for the two pressure waves <strong>of</strong> amplitude 1.2 <strong>and</strong> 0.8 which have been<br />

used in previous sections <strong>of</strong> this chapter, consider them to be superposed in a pipe <strong>of</strong> 25 mm<br />

diameter with the compression wave pi moving rightward. The reference conditions are also<br />

as used before at To is 20°C or 293K <strong>and</strong> po as 101,325 Pa. However, pressure drop occurs<br />

only as a result <strong>of</strong> particle movement so it is necessary to define a time interval for the superposition<br />

process to occur. Consider that the waves are superposed at the pressure levels<br />

indicated for a period <strong>of</strong> 2° crankshaft in the duct <strong>of</strong> an engine running at 1000 rpm. This<br />

represents a time interval, dt, <strong>of</strong>:<br />

or dt = = 0.333 x 10" 3 s<br />

6x1000<br />

6 60 0<br />

dt = x — = — s (2.3.9)<br />

360 N 6N<br />

80

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