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Design and Simulation of Two Stroke Engines

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<strong>Design</strong> <strong>and</strong> <strong>Simulation</strong> <strong>of</strong> <strong>Two</strong>-<strong>Stroke</strong> <strong>Engines</strong><br />

The variations for the geometry <strong>of</strong> engine ports as conceived by practicing designers can<br />

be quite diverse, but they fall into two categories, the simple or the complex. The simple port<br />

layout is shown in Fig. 5.1(a) <strong>and</strong> the complex is illustrated in Fig. 5.1(b).<br />

The simple port layout with piston crown control<br />

This is sketched in Fig. 5.1(a) <strong>and</strong> typically applies to the exhaust <strong>and</strong> scavenge ports.<br />

The crankshaft has turned an angle, 6, from the top dead center, tdc, position <strong>and</strong> the piston<br />

has moved a length, xe, from the tdc point, having uncovered a port at an angle, 81, from tdc,<br />

<strong>and</strong> will fully uncover it after turning an angle, 62; the piston travel lengths are xei <strong>and</strong> xe2,<br />

respectively. For exhaust <strong>and</strong> scavenge (transfer) ports, almost universally, the value <strong>of</strong> 82 is<br />

180° or at bdc, in which case the value <strong>of</strong> X02 is the stroke length, Lst.<br />

The area <strong>of</strong> the port at any juncture is shown in the figure as Ae for a rectangular port <strong>of</strong><br />

width, xp, <strong>and</strong> top <strong>and</strong> bottom corner radii, rt <strong>and</strong> it,, respectively.<br />

The width across the port, xpe, at any crankshaft angle, 6, will be determined by the<br />

piston position being in the middle <strong>of</strong> the port, or across either <strong>of</strong> the corner radii, <strong>and</strong> is found<br />

from simple geometrical considerations, thus:<br />

if x0 < rt + xei then xp6 = xp - 2rt + 2^rt 2 - (rt - x6 + xei) (5.2.1)<br />

if xe > rt + xei <strong>and</strong> xe < xe2 - rb then xp0 = xp<br />

(5.2.2)<br />

if x0 > xei - rb then xp0 = xp - 2rb + 2^rb - (rb - xe2 + xe) 2 (5.2.3)<br />

The area <strong>of</strong> the port is then given by, where an incremental crankshaft movement, d8, is<br />

accompanied by a corresponding incremental piston movement, dx:<br />

e=e<br />

dx<br />

A0= Jxp9dx= J xp0— d8 (524)<br />

x=xe, 6=0,<br />

This is a relatively complex piece <strong>of</strong> calculus, <strong>and</strong> is much more readily solved on a<br />

computer by conducting the calculation in even increments <strong>of</strong> angle, thereby conducting the<br />

integral as a simple summation process for any port. The information is loaded into a data<br />

file, <strong>and</strong> by linearly interpolating from that data file, the value <strong>of</strong> port area can be determined<br />

at any given point within the computation. It is seen thus:<br />

. ^ 9 x p9 + X p8+A6 / >><br />

A e - la I v x e+A8~ x eJ (5.2.5)<br />

8=6,<br />

The summation can be conducted equally effectively by employing even increments <strong>of</strong><br />

angle, A6, <strong>of</strong> 1 ° crankshaft, or even increments <strong>of</strong> piston movement, Ax, <strong>of</strong> 0.1 mm.<br />

360

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