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Design and Simulation of Two Stroke Engines

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<strong>Design</strong> <strong>and</strong> <strong>Simulation</strong> <strong>of</strong> <strong>Two</strong>-<strong>Stroke</strong> <strong>Engines</strong><br />

The solution <strong>of</strong> the above simultaneous equations gives (where the total area, At, is defined<br />

below):<br />

Xd =<br />

At = Ai + A2 + A3<br />

2A2Xi2+2A3Xi3+Xil(A1-A2-A3)<br />

At<br />

_2A1Xil+2A3Xi3+Xi2(A2-A3-A1)<br />

2A1Xil+2A2Xi2+Xi3(A3-A2-A1)<br />

X r3 = " (2.13.3)<br />

Perhaps not surprisingly, the branched pipe can act as either a contraction <strong>of</strong> area to the<br />

flow or an enlargement <strong>of</strong> area to the gas flow. In short, two pipes may be supplying one pipe,<br />

or one pipe supplying the other two, respectively. Consider these two cases where all <strong>of</strong> the<br />

pipes are <strong>of</strong> equal area, where the pressure waves employed as examples are the familiar<br />

pulses which have been used so frequently throughout this text.<br />

(a) A compression wave is coming down to the branch in pipe 1 through air <strong>and</strong> all other<br />

conditions in the other branches are "undisturbed"<br />

The compression wave has a pressure ratio <strong>of</strong> PJI = 1.2, or Xjj = 1.02639. The results <strong>of</strong><br />

the calculation using Eqs. 2.13.3 are:<br />

Xd= 0.9911 Xr2 = Xr3 = 1.01759 Prl= 0.940 Pr2 = Pr3=1.13<br />

As far as pipe 1 is concerned the result is exactly the same as that for the 2:1 enlargement<br />

in area in the previous section. In the branch, the incident wave divides evenly between the<br />

other two pipes, transmitting a compression wave onward <strong>and</strong> reflecting a rarefaction pulse.<br />

Pipe 1 is supplying the other two pipes, hence the effect is an expansion.<br />

(b) Compression waves <strong>of</strong> pressure ratio 1.2 are arriving as incident pulses in pipes 1 <strong>and</strong> 2<br />

leading up to the branch with pipe 3<br />

Pipe 3 has undisturbed conditions as Pj3 = 1.0. Now the branch behaves as a 2:1 contraction<br />

to this general flow, for the solutions <strong>of</strong> Eqs. 2.13.3 show:<br />

Xri=Xr2= 1.0088 Xr3 = 1.0352 Prl = Pr2 = 1.0632 Pr3 = 1.274<br />

116<br />

At

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