BAKER HUGHES - Drilling Fluids Reference Manual

HYDRAULICS
2.
V
0.408( 375 )
a = ---------------------------------- = 1.12 ft/ sec
12.515 2 – 4.5 2
Find the power law constants n and K.
θ 600 = 83
θ 300 = 51
θ 3 = 5
• Inside drillpipe and drill collar
n = 3.3
p 2
• Annulus
θ600
log--------- = 3.32log
83
----- = 0.70
51
θ 300
5.11 × θ
K 600
p = --------------------------
1022 n p
=
5.11
---------------------- × 83
= 3.32
1022 0.70
3. Find the effective viscosity.
θ300
n a = 0.5 log --------- = 0.5 log
51
----- = 0.50
5
• Drillpipe
θ 3
5.11
K × θ300
a = ------------------------- = ----------------------
5.11 × 51
= 11.53
511 n a
511 0.50
μe p
=
100K p
96V
------------ p
D
n p – 1
=
100 3.32 ( )
96
----------------------- ( 10.45 ) 0.70 – 1
= 62.45 c p
3.826
• Drill collar
μ ep
= 100( 3.32
96 19.34
) ------------------------ ( ) 0.70 – 1
= 47.34 cp
2.8125
• Annulus of drill collar and open hole
144V
μ e a
100K a
a ------------------ n a – 1
=
D 2 – D 1
=
100 11.53 ( )
-----------------------------
144( 3.40)
0.50 – 1
= 84.43 cp
9.875 – 7.25
• Annulus of drillpipe and open hole
μ e a
= 100( 11.53
144 1.98
) -------------------------- ( )
0.50 – 1
= 158.31 cp
9.875 – 4.5
• Annulus of drillpipe and casing
μ e a
= 100( 11.53)
-----------------------------
144( 1.12)
0.50 – 1
= 257.03 cp
12.515 – 4.5
BAKER HUGHES DRILLING FLUIDS
REFERENCE MANUAL
REVISION 2006 9-31