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BAKER HUGHES - Drilling Fluids Reference Manual

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HYDRAULICS<br />

4. Calculate hydraulic horsepower and impact force.<br />

QP (<br />

HHP n )<br />

-------------- = ( 375<br />

------------------------------ ) 1799<br />

= - ( ) = 394 hp<br />

1714 1714<br />

1.2732<br />

--------------------------------- ( )( 394<br />

HHP/in. 2 1.2732<br />

= ( )HHP<br />

= ---------------------------------- ) = 5.14 hp/in. 2<br />

D 2 ( 9.875) 2<br />

F ( 15.3) ( 375) 363<br />

i = ------------------------------------------- ( ) = 1078 lb<br />

1932<br />

f<br />

5. Calculate total nozzle area to maximize HHP or Impact Force. For maximum HHP, C = 0.65.<br />

A t<br />

= -------------------------------------------------------------<br />

Q<br />

2.96 ( 1238.5 )( C ) ( P<br />

--------------------------------------- ) 1/2<br />

ρ<br />

For maximum impact, C = 0.48<br />

=<br />

-------------------------------------------------------------------------<br />

375<br />

2.96 ( 1238.5<br />

= 0.2952 i n. 2<br />

)(.65) ( 3500<br />

------------------------------------------------- ) 1/2<br />

15.3<br />

6. Select jet sizes.<br />

375<br />

A t = -------------------------------------------------------------------------<br />

2.96 ( 1238.5<br />

= 0.3435 in. 2<br />

-------------------------------------------------- )(.48) ( 3500 ) 1/2<br />

15.3<br />

For 3 jets, N = 3; maximum HHP<br />

1<br />

1303.797<br />

⁄ 2<br />

1<br />

1303.797<br />

⁄ 2<br />

J 1 = ---------------------A<br />

N t = ---------------------0.2952 ( ) = 11 .3 → 11<br />

3<br />

⎛<br />

2<br />

1303.797<br />

( J<br />

------------------ A 1<br />

)<br />

1/2 ⎜ t<br />

– -----------------<br />

N – 1 ⎜ 1303.797⎟ ⎟⎞ = ------------------ 1303.797<br />

3 – 1<br />

0 .295 2 – -----------------<br />

11 2<br />

⎝<br />

⎛ 1303.797⎠<br />

⎞ 1/2 = 11.49 → 11<br />

⎝<br />

⎠<br />

2<br />

⎛<br />

1303.797<br />

( J<br />

---------------- A 1<br />

) + ( J 2<br />

) 2 ⎞ 1/2<br />

⎜ – -------------------------⎟<br />

1303.797<br />

N – 2 ⎜ t 1303.797 ⎟<br />

---------------- ⎛<br />

3 – 2<br />

0.2 952 –<br />

11<br />

----- 2 ---<br />

+<br />

--------<br />

11 2<br />

-⎞ 1/2 =<br />

= 11.59 → 12<br />

⎝ 1303.797 ⎠<br />

⎝<br />

⎠<br />

J 2 =<br />

J 3<br />

=<br />

For jets, N = 2; maximum HHP<br />

J 1<br />

Therefore, for maximum HHP with 3500 psi on the standpipe, we would choose 3 jets of 11, 11, and<br />

12.<br />

J<br />

2<br />

=<br />

=<br />

1/2<br />

1303.797 1303.797<br />

---------------------A t = --------------------- ( 0.2952 ) 1/2 = 13.87 → 14<br />

N<br />

2<br />

2<br />

(J 1 )<br />

t ---------------------<br />

N–<br />

1 ⎝<br />

⎜ 1303.797⎠<br />

⎟ ⎞ 1/2<br />

1303.797⎛<br />

--------------------- A –<br />

=<br />

1303.797 --------------------- ⎛<br />

2–<br />

1<br />

A – ---------------------<br />

142<br />

⎞ 1/2 = 13.74 14<br />

⎝ t 1303.797⎠<br />

→<br />

Therefore, for maximum HHP with 3500 psi on the standpipe, we would choose 2 jets of 14 and<br />

14.<br />

<strong>BAKER</strong> <strong>HUGHES</strong> DRILLING FLUIDS<br />

REFERENCE MANUAL<br />

REVISION 2006 9-35

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