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Apollonii Pergaei quae graece exstant cum ... - Wilbourhall.org

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CONICORUM LIBER I. 141<br />

eidem aequalis est; nam in figuris, <strong>quae</strong> iis duplo<br />

maiores sunt, hoc demonstratum est in propositione<br />

XLL quoniam igitur triangulus TAA a TKS siue<br />

T^S differt triangulo in A& descripto simili triangixlo<br />

'TzJAj uerum etiam triangulo T®A differt,<br />

triangulus<br />

T@A triangulo in A® descripto simili triangulo<br />

TAA aequalis est. quoniam igitur triangulus<br />

est [Eucl. I, 29] et HZ®<br />

BZE triangulo T^A similis<br />

triangulo T AS, eandem rationem habent^).<br />

et BZE<br />

in N& descriptus est inter rectam ordinatam centrumque,<br />

HZ& autem in -BJV ordinate ducta siue Z0; et<br />

propter ea, <strong>quae</strong> antea demonstrata sunt [prop. XLI],<br />

BZE sib HSZ differt triangulo in A& descripto simili<br />

triangulo TA A. ergo etiam triangulo TA& differt.<br />

Si recta parabolam contingens <strong>cum</strong> diametro concurrit,<br />

XLVL<br />

recta per punctum contactus diametro parallela<br />

ducta ad partes sectionis uersus rectas in sectione<br />

contingenti parallelas ductas in binas partes aequales<br />

secabit.<br />

sit parabola, cuius diametrus sit AB^j et sectionem<br />

contingat ATj per T autem rectae AA parallela<br />

ducatur STM^ et in sectione sumatur punctum aliquod<br />

A, ducaturque rectae AT parallela ANZE.<br />

dico, esse AN =^ NZ.<br />

ducantur ordinate 50, HZK^ AM^. quoniam<br />

1) Hoc est: latera eandem inter se rationem habent<br />

(Eucl. VI, 4); itaque in proportione FK: K& cet. substitui<br />

possunt rationes laterum triangulorum BZE, HZ0, ita jit<br />

condicioni<br />

propositionis 41 satis fiat.<br />

igitur propter ea, <strong>quae</strong> in propositione XLII demon-

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