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Apollonii Pergaei quae graece exstant cum ... - Wilbourhall.org

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CONICORUM LIBER III. 439<br />

et rE + EJ =^2H@. uerum etiam<br />

[prop. L]. ergo AB = TE + EA.<br />

AB = 2H0<br />

LIIL<br />

Si in hyperbola uel ellipsi uel circulo uel oppositis<br />

a terminis diametri rectae ordinate ductae parallelae<br />

rectae ducuntur, et ab iisdem terminis ad idem<br />

punctum lineae ductae rectae parallelas secant, rectangulum<br />

comprehensum partibus abscisis figurae eidem<br />

diametro adplicatae aequale est.<br />

sit una sectionum, quas diximus, ABVj cuius diametrus<br />

sit AFj et rectae ordinate ductae parallelae<br />

ducantur<br />

ducanturque<br />

AA, FE,<br />

ABEy<br />

FBA. dico, esse<br />

A^XEV<br />

figurae ad ^F adplicatae<br />

aequale.<br />

nam a 5 rectae<br />

ordinate<br />

ductae parallela<br />

ducatur B Z.<br />

itaque erit [I, 21], ut AZxZF.ZB^, ii?, latus<br />

transuersum ad rectum et AF^ ad figuram. uerum<br />

ZB) X {TZ : ZB). itaque<br />

AZXZF: ZB^ = {AZ :<br />

ratio figurae ad AF^ aequalis est<br />

est autem AZ\ZB = AT -.<br />

{ZB'.ZA)X {BZ\TZ).<br />

FE, rZ:ZB = rA:A^<br />

[Eucl. VI, 4] 5<br />

itaque ratio figurae ad<br />

AF^ = {FE : FA) X {AA : FA).<br />

Praeter nostram figuram aliam habet V in oppositis, sed<br />

imperfectam et litteris omissis; in nostra quoque litterae a<br />

manu 2 esse uideri possunt.

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