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Apollonii Pergaei quae graece exstant cum ... - Wilbourhall.org

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CONICORUM LIBER m. 425<br />

quadrata excedens, in ellipsi autem deficiens, sectionemque<br />

contingens recta ducitur <strong>cum</strong> rectis perpendicularibus<br />

concurrens, rectae a punctis concursus ad puncta<br />

adplicatione<br />

orta<br />

ductae ad puncta,<br />

<strong>quae</strong> diximus, rectos<br />

angulos<br />

sit<br />

efficiunt.<br />

aliqua sectionum,<br />

quas diximus,<br />

cuius axis sit ^B,<br />

perpendiculares autem<br />

AFj Bz] contingensque<br />

FEzI, et<br />

quartae parti figurae<br />

aequale in utramque<br />

partem adplicetur ita,<br />

ut diximus, AZX ZB<br />

et<br />

AHXHB, ducanturque<br />

TZ, Tif,<br />

^Z, ^H dico, angulos FZ^ et FHJ rectos esse.<br />

nam quoniam demonstrauimus , esse AFxBJ<br />

quartae parti figurae ad AB adplicatae aequale<br />

[prop. XLII], uerum etiam AZxZB quartae parti<br />

figurae aequale est, erit AFx ^B = AZ X ZB.<br />

itaque rA:AZ==ZB: 5z/ [Eucl. YI, 16].<br />

et anguli<br />

Sid Aj B positi recti sunt; itaque [Eucl. VI, 6]<br />

L AFZ = BZA, L AZr^Z^B. et quoniam LFAZ<br />

rectus est, L ATZ -\- AZF uni recto aequales sunt<br />

[Euci. I, 32]. et demonstrauimus etiam, esse<br />

L AFZ == ^Z5;<br />

itaque L TZA -{- ^ZB uni recto aequales erunt. ergo

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