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Introduction to Nanotechnology

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104 CARBON NANOSTRUCTURES<br />

electrons with oppositely paired electron spins. The electron charge distribution in<br />

an s state is spherically symmetric about the nucleus. These Is electrons do not<br />

participate in the chemical bonding. The next four electrons are in the N= 2 energy<br />

state, one in a spherically symmetric s orbital, and three in px, py, and pz orbitals,<br />

which have the very directed charge distributions shown in Fig. 5.la, oriented<br />

perpendicular <strong>to</strong> each other. This outer s orbital <strong>to</strong>gether with the three p orbitals<br />

form the chemical bonds of carbon with other a<strong>to</strong>ms. The charge distribution<br />

associated with these orbitals mixes (or overlaps) with the charge distribution of each<br />

other a<strong>to</strong>m being bonded <strong>to</strong> carbon. In effect, one can view the electron charge<br />

between the two a<strong>to</strong>ms of a bond as the glue that holds the a<strong>to</strong>ms <strong>to</strong>gether. On the<br />

basis of this simple picture the methane molecule, CH4, might have the structure<br />

shown in Fig. 5.lb, where the H-C bonds are at right angles <strong>to</strong> each other. However,<br />

Z Z<br />

Y Y Y<br />

X X X<br />

Figure 5.1. (a) Illustration of px, pv, and pz orbitals of the carbon a<strong>to</strong>m; (b) structure of methane<br />

CH4 assuming that the valence orbitals of carbon are pure px, p,,, and pz orbitals; (c) actual<br />

structure of CH4, which is explained by sp' hybridization.<br />

PZ

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