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3 months ago

Bộ đề thi thử THPT QG 2018 Các môn TOÁN - LÍ - HÓA Các trường THPT Cả nước CÓ HƯỚNG DẪN GIẢI (Lần 8) [DC11042018]

https://app.box.com/s/nhxs7vnw9na94twmj7hc0inbdjzwv940

https://twitter.com/daykemquynhon plus.google.com/+DạyKèmQuyNhơn www.facebook.com/daykem.quynhon http://daykemquynhon.blogspot.com http://daykemquynhon.ucoz.com Nơi bồi dưỡng kiến thức Toán - Lý - Hóa cho học sinh cấp 2+3 / Diễn Đàn Toán - Lý - Hóa 1000B Trần Hưng Đạo Tp.Quy Nhơn Tỉnh Bình Định Chỉ có D thõa mãn; vì OH − không tồn tại chung dung dịch với HCO − 3 Câu 28: Đáp án A Ta có phản ứng: CH 2 =CHCOOH + NaOH → CH 2 =CHCOONa + H 2 O. Ta có: n CH2=CHCOOH = 0,1 mol < n NaOh ⇒ n H2O = 0,1 mol. + Bảo toàn khối lượng ta có: m Rắn khan = 7,1 + 0,15×40 – 0,1×18 = 11,4 gam. Câu 29: Đáp án B Câu 30: Đáp án A n OH – = 0,52 ⇒ 2 phần bằng nhau mỗi phân chứa n OH – = 0,26 n = n ⇒ n = 0, 26 H2O − OH H2O ⇒ m = 0, 26.18 + 17,12 − 0,16.40 − 0,1.56 = 9,8⇒ n = 0,1 H3PO4 H3PO4 Suy ra được 2 muối HPO ; PO 2− 3− 4 4 Gọi số mol của mỗi muối là a;b m = 17,12 − m − m = 9,54 ⇒ 96 a + 95b = 9,54 2− 3− HPO 4 ; + PO4 2a + 3b = n = 0, 26 − OH Na K ( ) ( ) ⇒ a = 0,04; b = 0,06 ⇒ m = 0,04. 40 + 96 + 0,03 40.3 + 95.2 = 14,74 Câu 31: Đáp án D ↓ Từ tỉ lệ mol ta đặt: n CnH2n+1N = 3a và n CmH2m+1O2N = 2a. ⇒ 3a + 2a = n HCl pứ = 0,2 ⇒ a = 0,04 mol. ⇒ n CnH2n+1N = 0,12 và n CmH2m+1O2N = 0,08 mol Ta có: 0,12 × M CnH2n+1N + 0,08 × M CmH2m+1O2N = 14,2 gam. ⇔ 0,12×(14n+17) + 0,08×(14m+47) = 14,2 ⇔ 3n + 2m = 15. + Giải PT nghiệm nguyên ta có 2 cặp nghiệm thỏa mãn: ● TH 1 : n = 1 và m = 6 ⇒ Y là: C 6 H 13 O 2 N ⇒ m Muối = 0,08×(131+22) = 12,24 gam ⇒ Loại vì k có đáp án. ● TH 2 : n = 3 và m = 3 ⇒ Y là: C 3 H 7 O 2 N ⇒ m Muối = 0,08×(89+22) = 8,88 gam Câu 32: Đáp án D n NaOH = 0,1 mol ⇒ n Muối = n RCOONa = 0,1 mol. DIỄN ĐÀN TOÁN - - HÓA 1000B TRẦN HƯNG ĐẠO TP.QUY NHƠN + Đốt cháy 0,1 mol RCOONa ⇒ n H2O = 0,05 mol ⇒ n H = 0,1 mol ⇒ Muối là HCOONa. Sơ đồ ta có. MỌI YÊU CẦU GỬI VỀ HỘP MAIL DAYKEMQUYNHONBUSINESS@GMAIL.COM HOTLINE : +84905779594 (MOBILE/ZALO) https://daykemquynhonofficial.wordpress.com/blog/ DẠY KÈM QUY NHƠN OFFICIAL ST> : Đ/C 1000B TRẦN HƯNG ĐẠO TP.QUY NHƠN Trang 9 Đóng góp PDF bởi GV. Nguyễn Thanh Tú www.facebook.com/daykemquynhonofficial www.facebook.com/boiduonghoahocquynhonofficial

https://twitter.com/daykemquynhon plus.google.com/+DạyKèmQuyNhơn www.facebook.com/daykem.quynhon http://daykemquynhon.blogspot.com http://daykemquynhon.ucoz.com Nơi bồi dưỡng kiến thức Toán - Lý - Hóa cho học sinh cấp 2+3 / Diễn Đàn Toán - Lý - Hóa 1000B Trần Hưng Đạo Tp.Quy Nhơn Tỉnh Bình Định ⎧HCOOR ′ : a 0,1 ( a+ b) ( a+ c) b ⎪ ⎨HCOOH : b + NaOH → HCOONa + R ′ OH + H2O ⎪ 4g 6,8g 3,2g ⎩R ′ OH : c 6,18g + Dễ dàng tính được m H2O = 0,18 gam ⇒ n H2O = 0,01 mol ⇒ n HCOOR' = 0,1 – 0,01 = 0,09 mol. + Ta có n Ancol = a + c = (0,09 + c) > 0,09 ⇒ M Ancol < 3,2÷0,09 = 35,67 ⇒ Ancol là CH 3 OH ⇒ Este là HCOOCH 3 với số mol = 0,09 ⇒ m HCOOCH3 = 5,4 gam ⇒% m 5,4 × 100 HCOOCH3 = ×100% = 87,38% 6,18 Câu 33: Đáp án D Số thí nghiệm xảy ra ăn mòn điện hóa gồm: (1), (4) và (5) Câu 34: Đáp án A Câu 35: Đáp án B ● Giả sử 2 chất tan đó là: Fe(NO 3 ) 3 và HNO 3 dư . ⇒ n Fe(NO3)3 = n HNO3 dư = x. Bảo toàn electron ta có: 3n NO = 3n Fe ⇔ n NO = x. + Bảo toàn nguyên tố nito: ∑n HNO3 = 3n Fe(NO3)3 + n HNO3 dư + n NO . ⇔ y = 3x + x + x ⇔ y = 5x ● Giả sử 2 chất tan đó là Fe(NO 3 ) 3 và Fe(NO 3 ) 3 . ⇒ n Fe(NO3)3 = n Fe(NO3)2 = x 2 . Bảo toàn electron ta có: n NO = (3n Fe(NO3)3 + 2n Fe(NO3)2 ) ÷ 3 = 5x 6 + Ta có: ∑n HNO3 = 4n NO ⇔ y = 10x 3 Câu 36: Đáp án B Từ đáp án ⇒ X là este đơn chức. Y + NaOH → CH 4 + Na 2 CO 3 ⇒ Y là CH 3 COONa ⇒ Loại A và C. Z có phản ứng tráng gương ⇒ Loại D ⇒ X là CH 3 COOCH=CH 2 . DIỄN ĐÀN TOÁN - - HÓA 1000B TRẦN HƯNG ĐẠO TP.QUY NHƠN Câu 37: Đáp án A Bài này không cần dùng giả thiết đốt cháy, với chút suy luận là đủ để chọn đáp án. MỌI YÊU CẦU GỬI VỀ HỘP MAIL DAYKEMQUYNHONBUSINESS@GMAIL.COM HOTLINE : +84905779594 (MOBILE/ZALO) https://daykemquynhonofficial.wordpress.com/blog/ DẠY KÈM QUY NHƠN OFFICIAL ST> : Đ/C 1000B TRẦN HƯNG ĐẠO TP.QUY NHƠN Trang 10 Đóng góp PDF bởi GV. Nguyễn Thanh Tú www.facebook.com/daykemquynhonofficial www.facebook.com/boiduonghoahocquynhonofficial

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Bộ đề luyện thi THPT Quốc Gia Môn Ngữ Văn (2016)
CÁC TRẠNG THÁI VẬT LÝ CỦA POLYMER
ĐỘC HỌC MÔI TRƯỜNG VÀ SỨC KHỎE CỘNG ĐỒNG