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THÈSE Estimation, validation et identification des modèles ARMA ...

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Chapitre 2. Estimating weak structural V<strong>ARMA</strong> models 71<br />

2.7 Appendix of technical proofs<br />

We begin with a lemma useful to show the identifiability of ϑ0.<br />

Lemma 1. Assume that Σ0 is non singular and that A5 holds true. If<br />

A −1 −1<br />

0 B0Bϑ (L)Aϑ(L)Xt = A −1<br />

00B00ǫt with probability one and A −1<br />

0 B0ΣB ′ 0A−1′ 0 =<br />

A −1<br />

00B00Σ0B ′ 00A −1′<br />

00 , then ϑ = ϑ0.<br />

Proof : L<strong>et</strong> ϑ = ϑ0. Assumption A5 implies that either A −1<br />

0 B0ΣB ′ 0A−1′ 0 =<br />

A −1<br />

00B00Σ0B ′ 00A −1′<br />

00 or there exist matrices Ci such that Ci0 = 0 for some i0 > 0 and<br />

A −1<br />

0<br />

B0B −1<br />

ϑ<br />

−1 −1<br />

(z)Aϑ(z)−A 00B00Bϑ0 (z)Aϑ0(z) =<br />

By contradiction, assume that A −1<br />

0 B0B −1<br />

∞<br />

Ciz i .<br />

00B00ǫt =<br />

A −1 −1<br />

00B00Bϑ0 (L)Aϑ0(L)Xt with probability one. This implies that there exists λ = 0 such<br />

that λ ′ Xt−i0 is almost surely a linear combination of the components of Xt−i,i > i0.<br />

By stationarity, it follows that λ ′ Xt is almost surely a linear combination of the<br />

components of Xt−i,i > 0. Thus λ ′ ǫt = 0 almost surely, which is impossible when the<br />

variance Σ0 of ǫt is positive definite. ✷<br />

i=i0<br />

ϑ (L)Aϑ(L)Xt = A −1<br />

Proof of Theorem 2.1 : Note that, due to the initial conditions, {˜<strong>et</strong>(ϑ)} is not<br />

stationary, but can be approximated by the stationary ergodic process<br />

<strong>et</strong>(ϑ) = A −1 −1<br />

0 B0Bϑ (L)Aϑ(L)Xt. (2.12)<br />

From an extension of Lemma 1 in FZ, it is easy to show that sup ϑ∈Θ˜<strong>et</strong>(ϑ)−<strong>et</strong>(ϑ) → 0<br />

almost surely at an exponential rate, as t → ∞. We thus have<br />

where<br />

˜ℓn(ϑ)<br />

oP(1)<br />

= ℓn(ϑ) := 1<br />

n<br />

n<br />

lt(ϑ) as n → ∞,<br />

t=1<br />

lt(ϑ) = dlog(2π)+logd<strong>et</strong>Σe +e ′ t(ϑ)Σ −1<br />

e <strong>et</strong>(ϑ).<br />

Now the ergodic theorem shows that almost surely<br />

ℓn(ϑ) → dlog(2π)+Q(ϑ),<br />

where Q(ϑ) = logd<strong>et</strong>Σe +Ee ′ 1 (ϑ)Σ−1<br />

e e1(ϑ). We have<br />

Q(ϑ) = E{e1(ϑ0)} ′ Σ −1<br />

e {e1(ϑ0)}+logd<strong>et</strong>Σe<br />

+E{e1(ϑ)−e1(ϑ0)} ′ Σ −1<br />

e {e1(ϑ)−e1(ϑ0)}<br />

+2E{e1(ϑ)−e1(ϑ0)} ′ Σ −1<br />

e e1(ϑ0).

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