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Cambridge International A Level Biology Revision Guide

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<strong>Cambridge</strong> <strong>International</strong> A <strong>Level</strong> <strong>Biology</strong><br />

430<br />

Estimating numbers of mobile animals<br />

Quadrats are obviously no use for finding or counting<br />

mobile animals, so different methods have to be used<br />

for these.<br />

Small mammals, such as mice and voles, can be caught<br />

in traps that are filled with hay for bedding and suitable<br />

food as bait. Insects and other invertebrates, such as<br />

spiders, can be captured by sweep netting. Pond nets are<br />

used for sampling aquatic organisms. The techniques for<br />

this vary according to the size of the body of water, and<br />

whether it is still or moving. Single birds can be counted<br />

quite easily, although this does become more difficult in<br />

dense forest. Flocks of birds are much more difficult to<br />

count, although it can be done by counting a group of ten<br />

birds and estimating how many such groups there are.<br />

A good method of estimating the population size of<br />

mobile organisms, if used with care, is the mark–release–<br />

recapture technique. First, as many individuals as possible<br />

are caught. Each individual is marked, in a way that<br />

will not affect its future chance of survival. The marked<br />

individuals are counted, returned to their habitat and left<br />

to mix randomly with the rest of the population.<br />

When enough time has elapsed for the mixing to<br />

take place, another large sample is captured. The number<br />

of marked and unmarked individuals is counted. The<br />

proportion of marked to unmarked individuals is then<br />

used to calculate an estimate of the total number in the<br />

population (Worked example 1). For example, if you find<br />

that one-tenth of the second sample was marked, then<br />

you presume that you originally caught one-tenth of the<br />

population in your first sample. Your best estimate is<br />

therefore that the number in the population is ten times<br />

the number you caught and marked in your first sample.<br />

WORKED EXAMPLE 1<br />

The mark–release–recapture technique<br />

Brown planthoppers are a serious insect pest of rice.<br />

Some students used sweep nets to catch a large sample<br />

of planthoppers in a field of rice. Each animal was marked<br />

with a very small spot of non-toxic waterproof paint and<br />

then they were released across the field. The next day, a<br />

second large sample was caught.<br />

Number caught and marked in first sample = 247<br />

Number caught in second sample = 259<br />

Number in the second sample that had<br />

been marked = 16<br />

247 × 259<br />

So the estimated number in the population =<br />

16<br />

= 3998<br />

Simpson’s Index of Diversity<br />

When you have collected information about the<br />

abundance of the species in the area you are studying, you<br />

can use your results to calculate a value for the species<br />

diversity in that area. We can do this using Simpson’s<br />

Index of Diversity, D. One formula for this is:<br />

n<br />

D = 1 − ∑<br />

2<br />

N<br />

where n is the total number of organisms of a particular<br />

species, and N is the total number of organisms of all<br />

species (Worked example 2).<br />

Values of D range from 0 to 1. A value near 0 represents<br />

WORKED EXAMPLE 2<br />

Simpsonʼs Index of Diversity<br />

A sample was made of the animals living on two rocky<br />

shores. 10 quadrats were placed on each shore, and the<br />

number of animals of each species in each quadrat was<br />

counted. The results are shown in the table.<br />

Species<br />

Number of individuals, n<br />

Shore A Shore B<br />

painted topshells 24 51<br />

limpets 367 125<br />

dogwhelks 192 63<br />

snakelocks anemones 14 0<br />

beadlet anemones 83 22<br />

barnacles 112 391<br />

mussels 207 116<br />

periwinkles 108 93<br />

total number of<br />

individuals, N<br />

1107 861<br />

To determine Simpson’s Index for shore A, calculate<br />

n<br />

for each species, square each value, add them up and<br />

N<br />

subtract from 1. Repeat the procedure for shore B.<br />

Species<br />

Shore A<br />

n<br />

n<br />

N<br />

n<br />

2<br />

N<br />

painted topshells 24 0.022 0.000<br />

limpets 367 0.332 0.110<br />

dogwhelks 192 0.173 0.030<br />

snakelocks anemones 14 0.013 0.000<br />

beadlet anemones 83 0.075 0.006<br />

barnacles 112 0.101 0.010<br />

mussels 207 0.187 0.035<br />

periwinkles 108 0.098 0.010<br />

total number of<br />

individuals, N<br />

1107<br />

∑<br />

n 2<br />

N<br />

For shore A, Simpson’s Index of Diversity (D)<br />

= 1 − 0.201 = 0.799<br />

= 0.201

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