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Cambridge International A Level Biology Revision Guide

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<strong>Cambridge</strong> <strong>International</strong> AS <strong>Level</strong> <strong>Biology</strong><br />

Enzyme<br />

Substrate<br />

Maximum turnover K m<br />

number / per second / mol dm 3<br />

carbonic anhydrase carbon dioxide 600 000 8000<br />

penicillinase penicillin 2000 50<br />

chymotrypsin protein 100 5000<br />

lysozyme acetylglucosamine 0.5 6<br />

Table 3.2 Turnover numbers and K m<br />

values for four enzymes. Note that the unit for<br />

K m<br />

is a concentration. (The turnover number per second is the number of molecules<br />

of substrate that one molecule of an enzyme converts to product per second. This is<br />

related to V max<br />

.)<br />

64<br />

The significance of V max<br />

and K m<br />

values<br />

Knowing the values of V max<br />

and K m<br />

has a number of<br />

applications.<br />

■■<br />

■■<br />

■■<br />

■■<br />

■■<br />

■■<br />

It enables scientists to make computerised models of<br />

biochemical pathways or even the behaviour of whole<br />

cells because it helps to predict how each reaction in a<br />

proposed pathway will proceed and therefore how the<br />

enzymes will interact. The consequences of changing<br />

conditions such as temperature, pH or the presence of<br />

inhibitors can be built into the models.<br />

An enzyme’s preference for different substrates can be<br />

compared quantitatively.<br />

By understanding what affects enzyme efficiency,<br />

scientists may in future be able to design better<br />

catalysts, linking this to genetic engineering.<br />

For a commercially important enzyme, the<br />

performance of the same enzyme from different<br />

organisms can be compared.<br />

The calculations involved can be applied to other fields<br />

of biochemistry, such as antibody–antigen binding.<br />

Knowing K m<br />

means the proportion of active sites<br />

occupied by substrate molecules can be calculated for<br />

any substrate concentration.<br />

QUESTION<br />

3.9 Which of the four enzymes in Table 3.2 has the<br />

highest affinity for its substrate? Briefly explain<br />

your answer.<br />

Immobilising enzymes<br />

Enzymes have an enormous range of commercial<br />

applications – for example, in medicine, food technology<br />

and industrial processing. Enzymes are expensive. No<br />

company wants to have to keep buying them over and<br />

over again if it can recycle them in some way. One of the<br />

best ways of keeping costs down is to use immobilised<br />

enzymes.<br />

The enzyme lactase can be immobilised using alginate<br />

beads (Box 3.2). Milk is then allowed to run through the<br />

column of lactase-containing beads. The lactase hydrolyses<br />

the lactose in the milk to glucose and galactose. The milk<br />

is therefore lactose-free, and can be used to make lactosefree<br />

dairy products for people who cannot digest lactose.<br />

You can see that enzyme immobilisation has several<br />

obvious advantages compared with just mixing up the<br />

enzyme with its substrate. If you just mixed lactase with<br />

milk, you would have a very difficult task to get the lactase<br />

back again. Not only would you lose the lactase, but also<br />

you would have milk contaminated with the enzyme.<br />

Using immobilised enzymes means that you can keep and<br />

re-use the enzymes, and that the product is enzyme-free.<br />

Another advantage of this process is that the<br />

immobilised enzymes are more tolerant of temperature<br />

changes and pH changes than enzymes in solution. This<br />

may be partly because their molecules are held firmly in<br />

shape by the alginate in which they are embedded, and so<br />

do not denature as easily. It may also be because the parts<br />

of the molecules that are embedded in the beads are not<br />

fully exposed to the temperature or pH changes.

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