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Building Design and Construction Handbook - Merritt - Ventech!

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STRUCTURAL THEORY 5.35<br />

The bending moment under the 6000-lb load in Fig. 5.20a considering only the<br />

force to the left is 7000 � 10, or 70,000 ft-lb. The bending-moment diagram, then,<br />

between the left support <strong>and</strong> the first concentrated load is a straight line rising from<br />

zero at the left end of the beam to 70,000 ft-lb, plotted to a convenient scale, under<br />

the 6000-lb load.<br />

The bending moment under the 9000-lb load, considering the forces on the left<br />

of it, is 7000 � 20 � 6000 � 10, or 80,000 ft-lb. (It could have been more easily<br />

obtained by considering only the force on the right, reversing the sign convention:<br />

8000 � 10 � 80,000 ft-lb.) Since there are no loads between the two concentrated<br />

loads, the bending-moment diagram between the two sections is a sloping straight<br />

line.<br />

If the bending moment <strong>and</strong> shear are known at any section of a beam, the<br />

bending moment at any other section may be computed, providing there are no<br />

unknown forces between the two sections. The rule is:<br />

The bending moment at any section of a beam is equal to the bending<br />

moment at any section to the left, plus the shear at that section times the<br />

distance between sections, minus the moments of intervening loads. If the section<br />

with known moment <strong>and</strong> share is on the right, the sign convention must<br />

be reversed.<br />

For example, the bending moment under the 9000-lb load in Fig. 5.20a could<br />

also have been obtained from the moment under the 6000-lb load <strong>and</strong> the shear to<br />

the right of the 6000-lb load given in the shear diagram (Fig. 5.20b). Thus,<br />

80,000 � 70,000 � 1000 � 10. If there had been any other loads between the two<br />

concentrated loads, the moment of these loads about the section under the 9000-lb<br />

load would have been subtracted.<br />

Bending-moment diagrams for commonly encountered loading conditions are<br />

given in Figs. 5.30 to 5.41. These may be combined to obtain bending moments<br />

for other loads.<br />

5.5.6 Moments in Uniformly Loaded Beams<br />

When a bean carries a uniform load, the bending-moment diagram does not consist<br />

of straight lines. Consider, for example, the beam in Fig. 5.21a, which carries a<br />

uniform load over its entire length. As shown in Fig. 5.21c, the bending-moment<br />

diagram for this beam is a parabola.<br />

The reactions at both ends of a simply supported, uniformly loaded beam are<br />

both equal to wL/2 � W/2, where w is the uniform load in pounds per linear foot,<br />

W � wL is the total load on the beam, <strong>and</strong> L is the span.<br />

The shear at any distance x from the left support is R 1 wx � wL/2 � wx (see<br />

Fig. 5.21b). Equating this expression to zero, we find that there is no shear at the<br />

center of the beam.<br />

The bending moment at any distance x from the left support is<br />

��<br />

2<br />

x wLx wx w<br />

M � Rx� 1 wx � � � x(L � x) (5.51)<br />

2 2 2 2<br />

Hence:<br />

The bending moment at any section of a simply supported, uniformly loaded<br />

beam is equal to one-half the product of the load per linear foot <strong>and</strong> the<br />

distances to the section from both supports.<br />

The maximum value of the bending moment occurs at the center of the beam.<br />

It is equal to wL 2 /8 � WL/8.

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