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Building Design and Construction Handbook - Merritt - Ventech!

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9.56 SECTION NINE<br />

where A oh � area enclosed by centerline of the outermost closed transverse torsion<br />

reinforcement, in 2<br />

p h � perimeter of the centerline of the outermost closed transverse torsion<br />

reinforcement, in<br />

The reinforcement for torsion requires that<br />

� T � T (9.47)<br />

n u<br />

where T n � nominal torsional moment strength which � T s, the nominal torsional<br />

moment strength provided by torsion reinforcement<br />

Stirrups. The transverse reinforcement required for torsion is calculated from<br />

T � (2A Aƒ cot �)/s (9.48)<br />

n o t yv<br />

where s � spacing of torsion reinforcement in direction parallel to longitudinal<br />

reinforcement, in<br />

A o � 0.85 A oh<br />

A t � area of one leg of a closed stirrup within a distance s, in 2<br />

ƒ yv � yield strength of closed transverse torsion reinforcement, psi<br />

� � angle of concrete compression diagonals in truss analogy for torsion,<br />

which must not be taken smaller than 30� nor larger than 60� for nonprestressed<br />

members but may be taken as 45� for non-prestressed members<br />

<strong>and</strong> as 37.5� for prestressed members with an effective prestress<br />

force not less than 40% of the tensile strength of the longitudinal reinforcement<br />

For design, Eq. (9.48) can be re-arranged to calculate<br />

where � � strength-reduction factor, � 0.85<br />

A /s � T /(� 2 A ƒ cot �) (9.48a)<br />

t n o yv<br />

Since A t is defined as the area of one leg of a closed stirrup, it must be taken into<br />

account when the stirrup requirements for shear <strong>and</strong> torsion are added to provide<br />

the total amount of transverse reinforcement required. Stirrup area for shear, A v,is<br />

based on all the legs of a stirrup. If the required stirrup area for shear is A v/s, <strong>and</strong><br />

that for torsion is A t/s, the total amount of transverse reinforcement required to<br />

resist shear <strong>and</strong> torsion is calculated<br />

� �<br />

A A 2A<br />

v�t v t<br />

Total � � (9.49)<br />

s s s<br />

Longitudinal Reinforcement. The additional longitudinal reinforcement, A �, required<br />

for torsion is calculated from<br />

2<br />

Al � (A t/s)p h(ƒ yv/ƒ y�)cot<br />

� (9.50)<br />

where A t/s � amount calculated from Eq. (9.48a)<br />

ƒ y� � yield strength of longitudinal torsion reinforcement<br />

The amount of longitudinal torsion reinforcement in the flexural compression<br />

zone may be reduced by an amount equal to M u/(0.9 d ƒ y�), where M u is the factored<br />

moment acting at the section in combination with T u.

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