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Building Design and Construction Handbook - Merritt - Ventech!

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1.26 SECTION ONE<br />

after a specific number of years that it has been in service. Interest may be considered<br />

compounded annually.<br />

Future Value. Based on the preceding assumptions, a sum invested at time zero<br />

increases in time to<br />

n<br />

S � P(1 � i) (1.1)<br />

where S � future amount of money, equivalent to P, at the end of n periods of<br />

time with interest i<br />

i � interest rate<br />

n � number of interest periods, years<br />

P � sum of money invested at time zero � present worth of S<br />

Present Worth. Solution of Eq. (1.1) for P yields the present worth of a sum<br />

of money S at a future date:<br />

n<br />

P � S(1 � i) (1.2)<br />

The present worth of payments R made annually for n years is<br />

�n<br />

1 � (1 � i)<br />

P � R (1.3)<br />

i<br />

The present worth of the payments R continued indefinitely can be obtained from<br />

Eq. (1.3) by making n infinitely large:<br />

R<br />

P � (1.4)<br />

i<br />

Capital Recovery. A capital investment P at time zero can be recovered in n<br />

years by making annual payments of<br />

� �<br />

i i<br />

R � P � P � i (1.5)<br />

�n n<br />

1 � (1 � i) (1 � i) � 1<br />

When an item has salvage value V after n years, capital recovery R can be computed<br />

from Eq. (1.5) by subtraction of the present worth of the salvage value from the<br />

capital investment P.<br />

� �<br />

i<br />

�n<br />

R � [P � V(1 � i) ] � i (1.6)<br />

n (1 � i) � 1<br />

Example. To illustrate the use of these formulas, an economic comparison is made<br />

in the following for two air-conditioning units being considered for an office building.<br />

Costs are estimated as follows:<br />

Unit 1 Unit 2<br />

Initial cost $300,000 $500,000<br />

Life, years 10 20<br />

Salvage value $50,000 $100,000<br />

Annual costs $30,000 $20,000

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