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Building Design and Construction Handbook - Merritt - Ventech!

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5.90 SECTION FIVE<br />

O, the sum of the end moments in each member at O must be equal to U. Furthermore,<br />

all members must rotate at O through the same angle �, since they are<br />

assumed to be rigidly connected there. Hence, by the definition of fixed-end stiffness,<br />

the proportion of U induced in the end of each member at O is equal to the<br />

ratio of the stiffness of that member to the sum of the stiffnesses of all the members<br />

at the joint (Art. 5.11.3).<br />

FIGURE 5.74 Effect of an unbalanced moment<br />

at a joint in a frame.<br />

Suppose a moment of 100 ft-kips is<br />

applied at O, as indicated in Fig. 5.74b.<br />

The relative stiffness (or I/L) is assumed<br />

as shown in the circle on each member.<br />

The distribution factors for the moment<br />

at O are computed from the stiffnesses<br />

<strong>and</strong> shown in the boxes. For example,<br />

the distribution factor for OA equals its<br />

stiffness divided by the sum of the stiffnesses<br />

of all the members at the joint:<br />

3/(3 � 2 � 4 � 1) � 0.3. Hence, the<br />

moment induced in OA at O is 0.3 �<br />

100 � 30 ft-kips. Similarly, OB gets 10<br />

ft-kips, OC 40 ft-kips <strong>and</strong> OD 20 ftkips.<br />

Because the far ends of these members<br />

are fixed, one-half of these moments<br />

are carried over to them (Art.<br />

5.11.2). Thus M AO � 0.5 � 30 � 15;<br />

M BO � 0.5 � 10 � 5; M CO � 0.5 �<br />

40 � 20; <strong>and</strong> M DO � 0.5 � 20 � 10.<br />

Most structures consist of frames<br />

similar to the one in Fig. 5.74, or even<br />

simpler, joined together. Though the<br />

ends of the members are not fixed, the<br />

technique employed for the frame in<br />

Fig. 5.74b can be applied to find end<br />

moments in such continuous structures.<br />

Before the general method is presented, one short cut is worth noting. Advantage<br />

can be taken when a member has a hinged end to reduce the work of distributing<br />

moments. This is done by using the true stiffness of a member instead of the fixedend<br />

stiffness. (For a prismatic beam with one end hinged, the stiffness is threefourth<br />

the fixed-end stiffness; for a beam with variable I, it is equal to the fixedend<br />

stiffness times 1 � C LC R, where C L <strong>and</strong> C R are the carry-over factors for the<br />

beam.) Naturally, the carry-over factor toward the hinge is zero.<br />

When a joint is neither fixed nor pinned but is restrained by elastic members<br />

connected there, moments can be distributed by a series of converging approximations.<br />

All joints are locked against rotation. As a result, the loads will create<br />

fixed-end moments at the ends of every member. At each joint, a moment equal to<br />

the algebraic sum of the fixed-end moments there is required to hold it fixed. Then,<br />

one joint is unlocked at a time by applying a moment equal but opposite in sign<br />

to the moment that was needed to prevent rotation. The unlocking moment must<br />

be distributed to the members at the joint in proportion to their fixed-end stiffnesses<br />

<strong>and</strong> the distributed moments carried over to the far ends.<br />

After all joints have been released at least once, it generally will be necessary<br />

to repeat the process—sometimes several times—before the corrections to the fixed-

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