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Building Design and Construction Handbook - Merritt - Ventech!

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9.62<br />

TABLE 9.8 Tension Development Lengths, L d, for Grade 60 Uncoated Bars (Inches)<br />

Bar<br />

size no.<br />

Top bars<br />

ƒ� c<br />

Case 1 Case 2<br />

� 3,000 psi<br />

Other bars<br />

Case 1 Case 2<br />

Top bars<br />

ƒ� c<br />

Case 1 Case 2<br />

� 4,000 psi<br />

Other bars<br />

Case 1 Case 2<br />

Top bars<br />

ƒ� c<br />

Case 1 Case 2<br />

� 5,000 psi<br />

Other bars<br />

Case 1 Case 2<br />

3 22 32 17 25 19 28 15 22 17 25 13 19<br />

4 29 43 22 33 25 37 19 29 22 33 17 26<br />

5 36 54 28 41 31 47 24 36 28 42 22 32<br />

6 43 64 33 50 37 56 29 43 33 50 26 38<br />

7 63 94 48 72 54 81 42 63 49 73 37 56<br />

8 72 107 55 82 62* 93 48 71 55 83 43 64<br />

9 81 121 62 93 70 105 54 81 63 94 48 72<br />

10 91 136 70 105 79 118 61 91 70 105 54 81<br />

11 101 151 78 116 87 131 67 101 78 117 60 90<br />

14 121 181 93 139 105 157 81 121 94 140 72 108<br />

18 161 241 124 186 139 209 107 161 125 187 96 144<br />

NOTES:<br />

1. Values are based on Section 12.2.2 in ACI 318-99 <strong>Building</strong> Code.<br />

2. Case 1 <strong>and</strong> Case 2 are defined:<br />

Structural element<br />

Case<br />

Beams <strong>and</strong> columns Other elements<br />

1 Concrete cover �db, c.-c. bar<br />

spacing �2 db <strong>and</strong> with stirrups<br />

or ties throughout Ld not less than<br />

Code minimum<br />

Concrete over �db, c.-c. bar<br />

spacing �3 db 2 Concrete cover �db or c.-c. bar<br />

spacing �2 db Concrete cover �db or c.-c.<br />

bar spacing �3 db 3. Values are for normal-weight concrete.<br />

4. St<strong>and</strong>ard 90� or 180� end hooks may be used to replace part of the required development length. See Table 9.9.<br />

* Sample Calculation: For Case 1, bar size no. 8; using Eq. (9.55), Ld � (0.05ƒy ��� / �ƒ�)d c b where ƒy � 60,000<br />

psi; � � 1.3 for ‘‘top’’ bars; � � 1.0 for uncoated bars; � � 1.0 for normal-weight concrete; ƒ�c � 4,000 psi; <strong>and</strong> db �<br />

1.0 in. Thus, Ld � (0.05 � 60,000 � 1.3 � 1.0 � 1.0 / �4,000)(1.0) � 61.7<br />

or 62 in.

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