28.02.2013 Views

Building Design and Construction Handbook - Merritt - Ventech!

Building Design and Construction Handbook - Merritt - Ventech!

Building Design and Construction Handbook - Merritt - Ventech!

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

STRUCTURAL THEORY 5.143<br />

load that produces a unit deflection at midspan; thus, k � 48EI/L 3 , where E is the<br />

modulus of elasticity, psi; I the moment of inertia, in 4 ; <strong>and</strong> L the span, in, of the<br />

beam. The idealized mass equals W/g, where W is the weight of the load, lb, <strong>and</strong><br />

g is the acceleration due to gravity, 386 in/s 2 .<br />

Also, a single mass on a spring (Fig. 5.108d) may represent the rigid frame in<br />

Fig. 5.108c. In that case, k � 2 � 12EI/h 3 , where I is the moment of inertia, in 4 ,<br />

of each column <strong>and</strong> h the column height, in. The idealized mass equals the sum of<br />

the masses on the girder <strong>and</strong> the girder mass. (Weight of columns <strong>and</strong> walls is<br />

assumed negligible.)<br />

The spring <strong>and</strong> mass in Fig. 5.108b <strong>and</strong> d form a one-degree system. The degree<br />

of a system is determined by the least number of coordinates needed to define the<br />

positions of its components. In Fig. 5.108, only the coordinate y is needed to locate<br />

the mass <strong>and</strong> determine the state of the spring. In a two-degree system, such as<br />

one comprising two masses connected to each other <strong>and</strong> to the ground by springs<br />

<strong>and</strong> capable of movement in only one direction, two coordinates are required to<br />

locate the masses.<br />

If the mass with weight W, lb, in Fig. 5.108 is isolated, as shown in Fig. 5.108e<br />

it will be in dynamic equilibrium under the action of the spring force � ky <strong>and</strong> the<br />

inertia force (d 2 y/dt 2 )(W/g). Hence, the equation of motion is<br />

2 Wdy<br />

� ky � 0 (5.235)<br />

2<br />

g dt<br />

where y � displacement of mass, in, measured from rest position. Equation (5.235)<br />

may be written in the more convenient form<br />

The solution is<br />

2 2<br />

dy kg dy 2<br />

� y � � � y � 0 (5.236)<br />

2 2<br />

dt W dt<br />

y � A sin �t � B cos �t (5.237)<br />

where A <strong>and</strong> B are constants to be determined from initial conditions of the system,<br />

<strong>and</strong><br />

kg<br />

� � (5.238)<br />

�W<br />

is the natural circular frequency, rad/s.<br />

The motion defined by Eq. (5.237) is harmonic. Its natural period, s, is<br />

Its natural frequency, Hz, is<br />

�<br />

2� W<br />

T � � 2� (5.239)<br />

� kg

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!