Energy and Human Ambitions on a Finite Planet, 2021a
Energy and Human Ambitions on a Finite Planet, 2021a
Energy and Human Ambitions on a Finite Planet, 2021a
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A.6 Fracti<strong>on</strong>al Powers 366<br />
writing this set three times, all multiplied together, or (7 · 7 · 7 · 7) ×<br />
(7 · 7 · 7 · 7) × (7 · 7 · 7 · 7), which is just 12 sevens multiplied, or 7 12 .So<br />
we have discovered/formulated the rule:<br />
(x a ) b x a·b . (A.7)<br />
We multiply the exp<strong>on</strong>ents when raising the inner exp<strong>on</strong>ent to an outer<br />
<strong>on</strong>e.<br />
How about 3 2 · 3 5 ? What is the rule there? The process 21 is similar to<br />
before, exp<str<strong>on</strong>g>and</str<strong>on</strong>g>ing out to (3 · 3) × (3 · 3 · 3 · 3 · 3), which just looks like<br />
seven threes multiplied together, or 3 7 . Therefore, our rule is:<br />
x p · x q x (p+q) .<br />
(A.8)<br />
21: Note that some care must be exercised<br />
in selecting the example. For instance, picking<br />
both exp<strong>on</strong>ents as 2 would leave some<br />
ambiguity: is the result of 4 2 + 2, 2 × 2,or<br />
2 2 ?<br />
We add exp<strong>on</strong>ents when multiplying two pieces, each having their own<br />
exp<strong>on</strong>ent. Note that this does not work when the bases are unequal, as<br />
you could verify yourself for 3 2 · 5 4 .<br />
Finally, what about inversi<strong>on</strong>, or dividing by x n ? As a preview, a negative<br />
power is equivalent to putting the item in the denominator, so that<br />
x −1 1 x<br />
. To see this, c<strong>on</strong>sider Eq. A.8 in the case where p <str<strong>on</strong>g>and</str<strong>on</strong>g> q are<br />
opposite sign but the same magnitude. For instance, following the “add<br />
the exp<strong>on</strong>ents rule” we get that 3 4 ·3 −4 3 4−4 3 0 1, because anything<br />
raised to the zero power is 1. 22 The <strong>on</strong>ly thing we can multiply into<br />
1<br />
3 · 3 · 3 · 3 in order to get 1 is<br />
3·3·3·3 . This means that 3−4 is the same as<br />
1/3 4 , or more generally:<br />
1<br />
x n x−n .<br />
(A.9)<br />
Negative exp<strong>on</strong>ents therefore flip the c<strong>on</strong>structi<strong>on</strong> to the denominator,<br />
or denote a divisi<strong>on</strong> rather than multiplicati<strong>on</strong>.<br />
22: Think of the exp<strong>on</strong>ent as how many instances<br />
of a number are multiplied together<br />
in a chain, implicitly all multiplied by 1. If<br />
we have zero instances of the number, then<br />
the implicit 1 is all we have left in the multiplicati<strong>on</strong>.<br />
In other words, 1 is the starting<br />
point for all multiplicati<strong>on</strong>s, just like zero<br />
is the starting point for all additi<strong>on</strong>s.<br />
A.6 Fracti<strong>on</strong>al Powers<br />
In the previous secti<strong>on</strong>, we <strong>on</strong>ly dealt with integer powers, so that we<br />
could write out 3 4 as 3 · 3 · 3 · 3. How would we possibly write 3 1.7 ?Yet<br />
it is mathematically well defined. A calculator has no trouble.<br />
We can get a hint from Eq. A.8. C<strong>on</strong>sider, for example, 5 1 2 · 5 1 2 . We know<br />
that we can just add the exp<strong>on</strong>ents, which in this case add to a tidy 1,<br />
meaning that the answer is just 5. Therefore we interpret 5 1 2 as the square<br />
root of 5, since multiplying it by itself yields 5. So we can re-express our<br />
familiar friend as a fracti<strong>on</strong>al power:<br />
x 1 2 <br />
√<br />
x. (A.10)<br />
In principle, then, we could approach 3 1.7 by taking the tenth-root of 3<br />
<str<strong>on</strong>g>and</str<strong>on</strong>g> raising it to 17 th power: 3 1.7 (3 1 10 ) 17 3 17<br />
10 .<br />
© 2021 T. W. Murphy, Jr.; Creative Comm<strong>on</strong>s Attributi<strong>on</strong>-N<strong>on</strong>Commercial 4.0 Internati<strong>on</strong>al Lic.;<br />
Freely available at: https://escholarship.org/uc/energy_ambiti<strong>on</strong>s.