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Energy and Human Ambitions on a Finite Planet, 2021a

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B.4 Ideal Gas Law 381<br />

B.4 Ideal Gas Law<br />

Another topic covered in chemistry classes that str<strong>on</strong>gly overlaps physics<br />

is the ideal gas law. This relati<strong>on</strong>ship describes the interacti<strong>on</strong>s between<br />

pressure, volume <str<strong>on</strong>g>and</str<strong>on</strong>g> temperature of a gas. In chemistry class, it is<br />

learned as<br />

PV nRT,<br />

(B.2)<br />

where P st<str<strong>on</strong>g>and</str<strong>on</strong>g>s for pressure (in Pascals 18 ), V is volume (cubic meters), n<br />

is the number of moles, T is temperature (in Kelvin), <str<strong>on</strong>g>and</str<strong>on</strong>g> R is called the<br />

gas c<strong>on</strong>stant, having the value<br />

R 8.314<br />

J<br />

mol · K .<br />

(B.3)<br />

18: A Pascal (Pa) is also a Newt<strong>on</strong> of force<br />

per square meter, which reduces to more<br />

fundamental units of J/m 3 (Joules of energy<br />

per cubic meter).<br />

To get degrees in Kelvin, add 273.15 (273 am<strong>on</strong>g friends) to the temperature<br />

in Celsius. 19 St<str<strong>on</strong>g>and</str<strong>on</strong>g>ard atmospheric pressure is about 10 5 Pa. 20<br />

20: 1 atmosphere is 101,325<br />

19: And T( ◦ F) 1.8 · T( ◦ C) + 32.<br />

Pa.<br />

Example B.4.1 Let’s say we have a gas at “st<str<strong>on</strong>g>and</str<strong>on</strong>g>ard temperature <str<strong>on</strong>g>and</str<strong>on</strong>g><br />

pressure” (STP), meaning 0 ◦ C (273 K) <str<strong>on</strong>g>and</str<strong>on</strong>g> 1.013 × 10 5 Pa. How much<br />

volume would <strong>on</strong>e mole of gas 21 occupy?<br />

We have everything we need to solve for volume, so<br />

21: It may be surprising, but the ideal gas<br />

law does not care what element or molecule<br />

we are c<strong>on</strong>sidering!<br />

V nRT<br />

P<br />

<br />

(1 mol)(8.314 J/K/mol)(273 K)<br />

1.013 × 10 5 Pa<br />

≈ 0.0224 m 3 22.4L.<br />

Okay; lots going <strong>on</strong> here. After the three values in the numerator are<br />

multiplied, the <strong>on</strong>ly surviving unit is J (Joules of energy). The unit in<br />

the denominator is Pascals, but this is equivalent to Joules per cubic<br />

meter. So the answer emerges in cubic meters, as a volume should.<br />

Since a cubic meter is 1,000 liters, we find that a mole of gas at STP<br />

occupies 22.4 L—a number memorized by many a chemistry student!<br />

Physicists prefer a variant of the ideal gas law that derives from the<br />

study of “statistical mechanics,” which is practically syn<strong>on</strong>ymous with<br />

thermodynamics <str<strong>on</strong>g>and</str<strong>on</strong>g> relates to the study of interacti<strong>on</strong>s between large<br />

ensembles of particles. The form looks pretty familiar, still:<br />

PV Nk B T.<br />

(B.4)<br />

Pressure, volume, <str<strong>on</strong>g>and</str<strong>on</strong>g> temperature are all unchanged, <str<strong>on</strong>g>and</str<strong>on</strong>g> expressed<br />

in the same units as before. Now, N describes the number of particles<br />

(quite large, usually), <str<strong>on</strong>g>and</str<strong>on</strong>g> k B is called the Boltzmann c<strong>on</strong>stant, having a<br />

value<br />

k B 1.3806 × 10 −23 J K . (B.5)<br />

Notice that N, the number of particles, <str<strong>on</strong>g>and</str<strong>on</strong>g> n, the number of moles,<br />

differs simply by a factor of Avogadro’s number, N A 6.022 × 10 23 .<br />

Indeed, if we multiply N A by k B , we get 8.314, <str<strong>on</strong>g>and</str<strong>on</strong>g> are back to R. 22<br />

22: The units work, too, since N A effectively<br />

has units of a number (of particles) per mole.<br />

© 2021 T. W. Murphy, Jr.; Creative Comm<strong>on</strong>s Attributi<strong>on</strong>-N<strong>on</strong>Commercial 4.0 Internati<strong>on</strong>al Lic.;<br />

Freely available at: https://escholarship.org/uc/energy_ambiti<strong>on</strong>s.

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