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Radio Frequency Integrated Circuit Design - Webs

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86 <strong>Radio</strong> <strong>Frequency</strong> <strong>Integrated</strong> <strong>Circuit</strong> <strong>Design</strong><br />

a source resistance of 50�. The matching circuit must have a bandwidth of<br />

200 MHz and the circuit is to operate at 2 GHz.<br />

Solution<br />

The matching circuit will look much like that shown in Figure 4.25. We will<br />

use the secondary of the transformer as a resonant circuit so that there will be<br />

no reactance at 2 GHz. We first add capacitance in parallel with the input<br />

capacitance so that the circuit will have the correct bandwidth: Using (4.30),<br />

C total =<br />

1<br />

R BW =<br />

1<br />

= 7.96 pF<br />

(100�)(2� � 200 MHz)<br />

Note that the secondary ‘‘sees’’ 100� total, due to 200� from the load<br />

and 200� from the source resistance. This means that C extra must be 6.96 pF.<br />

Now, to resonate at 2 GHz, this means that the secondary of the transformer<br />

must have an inductance of<br />

L s =<br />

1<br />

� 2 o C s<br />

1<br />

=<br />

(2� � 2 GHz) 2 = 0.8 nH<br />

(7.96 pF)<br />

Now we must set the inductance ratio to turn 200� into 50�:<br />

L p =<br />

R effR L L s k 2<br />

R 2<br />

L − � 2 o L 2 s (1 − k 2 ) 2<br />

50� �200� �0.8 nH � (0.8)<br />

=<br />

2<br />

(200�) 2 − (2� � 2 GHz) 2 (0.8 nH) 2 (1 − 0.8 2 ) 2<br />

= 0.13 nH<br />

Figure 4.25 Transformer matching network used to match the input of a transistor.

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