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Radio Frequency Integrated Circuit Design - Webs

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282 <strong>Radio</strong> <strong>Frequency</strong> <strong>Integrated</strong> <strong>Circuit</strong> <strong>Design</strong><br />

where R bias is the tail resistor that is serving as a current source, I BQ is the<br />

quiescent bias current before oscillations begin, and VBEQ is the quiescent base<br />

emitter voltage of Q 1 or Q 2. It is assumed that VBEQ is constant in this<br />

expression, which is a good approximation for the half cycle when the transistor<br />

is on. In the other half cycle, the denominator will force the expression to zero<br />

for any reasonable value of V tank (V tank >> v T ), so the approximation will not<br />

seriously affect the shape of the resulting waveform.<br />

This expression can be used to find the average dc operating current in<br />

the circuit (which will be higher than the quiescent current). This current also<br />

depends on the final amplitude of the VCO.<br />

2�<br />

I AVE = 1<br />

2� �<br />

0<br />

I BQ + |V tank cos (� )|<br />

2R bias<br />

V tank<br />

v<br />

cos (� )<br />

1 + e T<br />

d� ≈ I BQ + V tank<br />

�R bias<br />

(8.70)<br />

The fundamental component of the current can also be extracted from<br />

(8.69) as before.<br />

i fund = 2<br />

�<br />

� �<br />

�IBQ +<br />

0 |Vtank cos (� )|<br />

2R bias<br />

V tank<br />

1 + e<br />

v T cos (� ) �cos (� ) d� ≈ 2<br />

� I BQ + V tank<br />

4R bias<br />

(8.71)<br />

This allows us to determine the ratio of current at the fundamental to<br />

average current:<br />

k = i fund<br />

=<br />

I AVE<br />

2<br />

� I BQ + V tank<br />

4R bias<br />

I BQ + V tank<br />

�Rbias<br />

(8.72)<br />

In the limit of large and small V tank, it can be seen that k is bounded by<br />

2 �<br />

≤ k ≤<br />

� 4<br />

(8.73)<br />

Therefore, the oscillation amplitude can once again be given in terms of<br />

dc current as

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