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Radio Frequency Integrated Circuit Design - Webs

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262 <strong>Radio</strong> <strong>Frequency</strong> <strong>Integrated</strong> <strong>Circuit</strong> <strong>Design</strong><br />

would like to make them as large as possible to minimize the loss (and the<br />

noise). We get large R p by having large inductor Q, and we get large r e,tank by<br />

using a large value of the capacitive transformer (by making C 2 bigger than<br />

C 1). Note that, as before, the value of g m as specified in (8.38) or (8.39) is the<br />

value that makes loop gain equal to 1, which is the condition for marginal<br />

oscillation. To guarantee startup, loop gain is set greater than 1 or g m is set<br />

greater than the value specified in the above equations.<br />

Note in (8.39) that re seems to have disappeared; however, it was absorbed<br />

by assuming that g m = 1/re .<br />

8.8 Negative Resistance Generated by the Amplifier<br />

In the next few sections, we will explicitly derive formulas for how much negative<br />

resistance is generated by each type of oscillator.<br />

8.8.1 Negative Resistance of Colpitts Oscillator<br />

In this section, an expression for the negative resistance of the oscillators will<br />

be derived. Consider first the common-base Colpitts configuration with the<br />

negative resistance portion of the circuit replaced by its small-signal model<br />

shown in Figure 8.17. Note that v�′ and the current source have both had their<br />

polarity reversed for convenience.<br />

An equation can be written for v�′ in terms of the current flowing through<br />

this branch of the circuit.<br />

ii + g mv�′ =j�C2v�′ + v�′<br />

Figure 8.17 Small-signal model for the Colpitts common-base negative resistance cell.<br />

re<br />

(8.40)

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