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Radio Frequency Integrated Circuit Design - Webs

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neg =<br />

Voltage-Controlled Oscillators<br />

g m<br />

g m<br />

� 2 =<br />

C 1C2 � 2 C 1Ctotal<br />

− g m<br />

� 2 C 2 1<br />

To find the minimum current, we find the maximum rneg by taking the<br />

derivative with respect to C 1.<br />

This leads to<br />

∂rneg<br />

∂C 1<br />

=<br />

−g m<br />

� 2 C 2 1 C total<br />

C 1 = 2C total<br />

+ 2g m<br />

� 2 C 3 1<br />

which means that the maximum obtainable negative resistance is achieved when<br />

the two capacitors are equal in value and twice the total capacitance. In this<br />

case, C 1 = C 2 = 1.1258 pF.<br />

Now the loss in the resonator at 3 GHz is due to the finite Q of the<br />

inductor.<br />

The series resistance of the inductor is<br />

rs = �L<br />

Q<br />

= (2� � 3 GHz)5 nH<br />

5<br />

= 0<br />

= 18.85�<br />

Therefore, rneg = r s = 18.85�. Noting that g m = I c /v T ,<br />

Ic = � 2 C 1C2vT rneg<br />

= (2� � 3 GHz) 2 (1.1258 pF) 2 (25 mV)(18.85�)<br />

= 212.2 �A<br />

In the case of the −Gm oscillator there is no capacitor ratio to consider.<br />

The parallel resistance of the inductor is<br />

R p = �LQ = (2� � 3 GHz)5 nH(5) = 471.2�<br />

Therefore rneg = R p = 471.2�. Noting again that g m = I c /v T<br />

Ic = 2vT<br />

R p<br />

= 2(25 mV)<br />

471.2�<br />

= 106.1 �A<br />

267

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