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Radio Frequency Integrated Circuit Design - Webs

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116 <strong>Radio</strong> <strong>Frequency</strong> <strong>Integrated</strong> <strong>Circuit</strong> <strong>Design</strong><br />

V1 = Z 11I1 + Z 12I2<br />

0 = Z 21I 1 + Z 22I 2<br />

The second equation can be solved for I2:<br />

I2 =− Z 21I1<br />

Z 22<br />

(5.15)<br />

(5.16)<br />

Thus, I2 can now be removed from the first equation, and solving for<br />

Z in = V1 /I1:<br />

Z port1 = Z 11 − Z 12Z21<br />

Z 22<br />

(5.17)<br />

Equivalently, if we look from port 2 to ground, the impedance becomes<br />

Z port2 = Z 22 − Z 12Z21<br />

Z 11<br />

(5.18)<br />

Note that, referring to Figure 5.12, this effectively grounds out both C 1<br />

and R 1 or C 2 and R 2. Thus, the Q will not necessarily be the same looking<br />

from both ports. In fact, the Q will be marginally higher in the case of a regular<br />

structure looking from the side with no underpass, as there will be less loss.<br />

Also note that the side with no underpass will have a higher self-resonance<br />

frequency.<br />

Often designers want to use inductors in a differential configuration. This<br />

means that both ends of the inductor are connected to active points in the<br />

circuit and neither side is connected to ground. In this case, we can define the<br />

impedance seen between the two ports:<br />

Starting again with the Z parameters, the voltage difference applied across<br />

the structure is now<br />

V1 − V2 = Z 11I1 + Z 12I2 − Z 21I1 − Z 22I2<br />

(5.19)<br />

V1 − V2 = I1(Z 11 − Z 21) − I2(Z 22 − Z 12) (5.20)<br />

Because the structure is symmetric, we make the assumption that I1 =<br />

−I2. Thus,<br />

Z diff = V1 − V2<br />

I1<br />

= Z 11 + Z 22 − Z 12 − Z 21<br />

(5.21)

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