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Radio Frequency Integrated Circuit Design - Webs

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The Use and <strong>Design</strong> of Passive <strong>Circuit</strong> Elements in IC Technologies<br />

diffuse into the silicon. When metals such as copper diffuse into silicon, they<br />

cause junctions to leak, seriously impairing the performance of transistors. A<br />

contact layer is used to connect this tungsten layer to the active circuitry in the<br />

silicon. Higher levels of metal can be connected to adjacent layers using conductive<br />

plugs that are commonly called vias. Whereas metal can be made in almost<br />

any shape desired by the designer, the vias are typically limited to a standard<br />

square size. However, it is possible to use arrays of vias to reduce the resistance.<br />

Higher metal layers are often made out of aluminum, as it is much less<br />

resistive than tungsten. In some modern processes, copper, which has even lower<br />

resistance than aluminum, may be available. The top level of metal will often<br />

be made much thicker than the lower levels to provide a low resistance routing<br />

option. However, the lithography for this layer may be much coarser than that<br />

of underling layers. Thus, the top layers can accommodate a lower density of<br />

routing lines.<br />

5.3 Sheet Resistance and the Skin Effect<br />

All conductive materials can be characterized by their resistivity � or their<br />

conductivity �. These two quantities are related by<br />

� = 1<br />

�<br />

97<br />

(5.1)<br />

Resistivity is expressed as ohm-meters (�m). Knowing the geometry of a<br />

metal and its resistivity is enough to estimate the resistance between any two<br />

points connected by the metal. As an example, consider the conductor shown<br />

in Figure 5.2. To find the resistance along its length, divide the resistivity of<br />

the metal by the cross-sectional area and multiply by the length.<br />

R = �L<br />

Wt<br />

Figure 5.2 Rectangular conductor with current flowing in the direction of L.<br />

(5.2)

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