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Radio Frequency Integrated Circuit Design - Webs

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190 <strong>Radio</strong> <strong>Frequency</strong> <strong>Integrated</strong> <strong>Circuit</strong> <strong>Design</strong><br />

This means that, of the designs presented so far, an LNA with shunt feedback<br />

will have to be used. This can be combined with a common-base amplifier to<br />

provide better frequency response and an output buffer to avoid the problem<br />

of loading the circuit. A first cut at a topology that could satisfy the requirements<br />

is shown in Figure 6.37. Note that emitter degeneration has been added to this<br />

circuit. Degeneration will almost certainly be required due to the linearity<br />

requirement. We have left the current source as ideal for this example. Also,<br />

we are not including the bias circuitry that will be needed at the base of Q 1.<br />

The first specification we will satisfy is the requirement of 8-mA total<br />

supply current. It may even be possible to do this design with less current. The<br />

trade-off is that as the current is decreased, R E must be increased to deliver the<br />

same linearity, and this will affect noise. We will begin this design using all the<br />

allowed current, and at the end, we will consider the possibility of reducing<br />

the current in a second iteration.<br />

The total current must be divided between the two stages of this amplifier.<br />

The buffer must have enough current so that it continues to operate properly<br />

even when it has to deliver a lot of current in the presence of large signals.<br />

Since the load resistance is large, the buffer will have to drive an effective<br />

resistance of approximately R f + 75�. This is expected to be a few hundred<br />

ohms and will require several hundreds of microamps of ac current. We will<br />

start with 3 mA in the buffer and 5 mA in the driver stage.<br />

We can now start to size the resistors and capacitor in the circuit by<br />

considering linearity. An IIP3 of 6 dBm in a 75� system, assuming that the<br />

input is matched, means that the IIP3 in terms of voltage will be 546 mVrms.<br />

Since we have assumed a current of 5 mA in the driver, we can now use (6.85)<br />

to determine the size of R E :<br />

Figure 6.37 Broadband LNA sample circuit.

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