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Digital Electronics: Principles, Devices and Applications

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Logic Gates <strong>and</strong> Related <strong>Devices</strong> 95+VABYCDFigure 4.37 Example 4.13.Example 4.13Refer to the logic arrangement of Fig. 4.37. Write the logic expression for the output Y.SolutionThe NAND gates used in the circuit are open collector gates. Paralleling of the two NAND gates atthe input leads to a WIRE-AND connection. Therefore the logic expression at the point where the twooutputs combine is given by the equationUsing DeMorgan’s theorem (discussed in Chapter 6 on Boolean algebra),ABCD (4.9)ABCD = AB + CD (4.10)The third NAND is wired as an inverter. Therefore, the final output can be written asY = AB + CD (4.11)4.10 Fan-Out of Logic GatesIt is a common occurrence in logic circuits that the output of one logic gate feeds the inputs of severalothers. It is not practical to drive the inputs of an unlimited number of logic gates from the output ofa single logic gate. This is limited by the current-sourcing capability of the output when the output ofthe logic gate is HIGH <strong>and</strong> by the current-sinking capability of the output when it is LOW, <strong>and</strong> alsoby the requirement of the inputs of the logic gates being fed in the two states.To illustrate the point further, let us say that the current-sourcing capability of a certain NAND gateis I OH when its output is in the logic HIGH state <strong>and</strong> that each of the inputs of the logic gate that it isdriving requires an input current I IH , as shown in Fig. 4.38(a). In this case, the output of the logic gatewill be able to drive a maximum of I OH /I IH inputs when it is in the logic HIGH state. When the outputof the driving logic gate is in the logic LOW state, let us say that it has a maximum current-sinkingcapability I OL , <strong>and</strong> that each of the inputs of the driven logic gates requires a sinking current I IL ,asshown in Fig. 4.38(b). In this case the output of the logic gate will be able to drive a maximum of

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