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MAN Diesel 4.09
L27/38 GenSet Data
Fig. 4.09.02b: L<strong>is</strong>t of capacities for L27/38, 750 rpm
MAN B&W 98 → 50 MC/MC�C, 108 → 50 ME/ME�C, 70 → 60
ME�GI, 50 → 35 ME�B
MAN Diesel
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Cyl. 5 6 7 8 9
Max continues rating 750 RPM kW ,600 ,980 2,3 0 2,640 2,970
Engine driven pumps:
LT cooling water pump 2.5 bar m³/h 70 70 70 70 70
HT cooling water pump 2.5 bar m³/h 70 70 70 70 70
Lubricating oil main pump 8 bar m³/h 66 66 96 96 96
Separate pumps:
Max. Delivery pressure of cooling water pumps bar 2.5 2.5 2.5 2.5 2.5
Diesel oil pump (5 bar at fuel oil inlet A ) m³/h . 0 .34 .57 .79 2.0
Fuel oil supply pump (4 bar d<strong>is</strong>charge pressure) m³/h 0.54 0.66 0.77 0.88 0.99
Fuel oil circulating pump (8 bar at fuel oil inlet A ) m³/h . .36 .59 .8 2.04
Cooling capacity:
Lubricating oil kW 2 7 283 328 376 420
Charge air LT kW 55 392 436 473 504
Total LT system kW 372 675 764 849 924
Flow LT at 36°C inlet and 44°C outlet m³/h 40 70 70 70 70
Jacket cooling kW 402 486 573 664 754
Charge air HT kW 457 558 640 722 802
Total HT system kW 859 ,044 ,2 3 ,386 ,556
Flow HT at 44°Cinlet and 80°C outlet m³/h 2 22 27 32 38
Total from engine kW ,23 ,7 9 ,977 2,235 2,480
LT flow at 36°C inlet m³/h 40 70 70 70 70
LT temp. Outlet engine °C 62 55 58 6 64
(at 36°C and string cooling water system)
Gas Data:
Exhaust gas flow kg/h ,693 5,000 7,400 9,900 22,400
Exhaust gas temp. °C 330 305 305 305 305
Max. Allowable back press. bar 0.025 0.025 0.025 0.025 0.025
Air consumption kg/h ,662 4,600 7,000 9,400 2 ,800
Starting Air System:
Air consumption per start Nm 3 2.5 2.9 3.3 3.8 4.3
Heat Radiation:
Engine kW 54 64 75 68 73
Alternator kW (see separate data from the alternator maker)
The stated heat balances are based on tropical conditions.
The exhaust gas data (exhaust gas flow, exhaust gas temp.
and air consumption). are based on ISO ambient condition.
* The outlet temperature of the HT water <strong>is</strong> fixed to 80°C, and
44°C for the LT water
At different inlet temperature the flow will change accordingly.
Example: If the inlet temperature <strong>is</strong> 25°C then the LT flow will
change to (46-36)/(46-25)* 00 = 53% of the original flow.
The HT flow will not change.
178 48 63�6.1
198 42 09�1.4