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R. Meyer J. Köhler A. Homburg Explosives

R. Meyer J. Köhler A. Homburg Explosives

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319 Thermodynamic Calculation of Decomposition Reactions<br />

The total mole number n is not altered by the water gas reaction; K1, is<br />

therefore independent of the total pressure p, but depends on the<br />

temperature (W Table 36). Equation (5) can be written as<br />

K1 = n2 ·n4<br />

n1 · n5<br />

The reaction for NO formation must also be considered<br />

1/2 N2+CO2 = CO+NO<br />

with the equilibrium equation<br />

K2 =<br />

[CO] · [NO]<br />

[N2] 1/2 · [CO2] =<br />

K2 = öä p<br />

n<br />

n4 · n6<br />

öäääää<br />

n3 · n1<br />

p<br />

n n4 · p<br />

n n6<br />

( p<br />

n) 1/2 · n3 1/2 · p<br />

n n1<br />

or<br />

(5a)<br />

K2: equilibrium constant,<br />

p: total pressure; p/n-n1, etc., the partial pressures<br />

n: total number of moles<br />

Because NO formation involves an alteration of n, the equilibrium<br />

constant K2 depends not only on the temperature, but also on the total<br />

pressure p.<br />

For the calculation of the six unknown mol numbers n1 ... n6, there are<br />

six equations. Alteration of the mole numbers cause alteration of the<br />

values for the reaction heat, the reaction temperature, the reaction<br />

pressure, and hence the constants K1 and K2. Calculations without the<br />

aid of a computer must assume various reaction temperatures to solve<br />

the equation system, until the values for the reaction heat as a<br />

difference of the energies of formation and the internal energy of the<br />

reaction products are the same (as shown above for the detonation of<br />

industrial explosives). This is a long trial and error calculation; therefore<br />

the use of computer programs is much more convenient.<br />

For low caloric propellants and for highly negative balanced explosives,<br />

such as TNT, the formation of element carbon must be assumed<br />

(Boudouard equilibrium):<br />

CO2+C = 2 CO<br />

with the equilibrium equation<br />

K3 = [CO]2<br />

[CO2]<br />

Explosion fumes with a dark color indicate the formation of carbon.<br />

The calculation becomes more complicated, if dissociation processes<br />

(6)<br />

(7)

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