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Vol2 Derivadas, aplicaciones y temas especiales - CIMM

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38 Elementos de cálculo, volumen 2<br />

(c)Tenemos:<br />

(d)<br />

y ′ =<br />

=<br />

=<br />

=<br />

y ′ =<br />

=<br />

=<br />

=<br />

′<br />

<br />

x + ln x<br />

=<br />

x + 2<br />

(x + ln x) ′ (x + 2) − (x + ln x)(x + 2) ′<br />

(x + 2) 2<br />

(1 + 1<br />

x )(x + 2) − (x + ln x)<br />

(x + 2) 2<br />

3x + 2 − x ln x<br />

x(x + 2) 2<br />

′<br />

x + 3 ln(x − 2)<br />

[x + 3 ln(x − 2)] ′<br />

2 x + 3 ln(x − 2)<br />

1 + 3 1<br />

x−2<br />

2 x + 3 ln(x − 2)<br />

x + 1<br />

2(x − 2) x + 3 ln(x − 2)<br />

• Determine la derivada de las siguientes funciones:<br />

(a) y = xe x + x 2 (b) y = x2 + 1<br />

(d) y = √ x + 3e x<br />

e x − 3<br />

Solución: (a) y ′ = (xe x + x 2 ) ′ = (xe x ) ′ + (x 2 ) ′<br />

(b) y ′ =<br />

= (x) ′ e x + x(e x ) ′ + 2x<br />

= 1 · e x + x · e x + 2x = e x (1 + x) + 2x<br />

x 2 + 1<br />

e x − 3<br />

′<br />

(c) y = e x2 +2x−3<br />

= (x2 + 1) ′ (e x − 3) − (x 2 + 1)(e x − 3) ′<br />

(e x − 3) 2<br />

= 2x(ex − 3) − (x 2 + 1)e x<br />

(e x − 3) 2<br />

(c) y ′ = e x2 +2x−3 ′ x<br />

= e 2 +2x−3 2 ′ x<br />

(x + 2x − 3) = e 2 +2x−3<br />

(2x + 2)<br />

(d) y ′ √x ′<br />

= + 3ex = (x + 3ex ) ′<br />

2 √ 1 + 3ex<br />

=<br />

x + 3ex 2 √ x + 3ex

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