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Membrane and Desalination Technologies - TCE Moodle Website

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186 N.K. Shammas <strong>and</strong> L.K. Wang<br />

Maximum feed concentration:<br />

Cf max ¼ð3:16 10 6 Þ DL; From ð4Þ<br />

Cf max ¼ 3:16 10 6<br />

2 particles=L;<br />

Cf max ¼ 6:32 10 4 particles=L: (4Þ<br />

Select a feed challenge particle concentration between the minimum (2 10 4 particles/L)<br />

<strong>and</strong> the maximum (6.32 10 6 particles/L). Arbitrarily:<br />

Ctest ¼ 5 10 4 particles=L:<br />

Step 3: Determine the total challenge particulate population required for the test solution.<br />

TCCP ¼ CtestVtest; From ð6Þ (6Þ<br />

where Ctest =5 10 4 particles/L (as calculated in step 2 above), Vtest = 6,070 L (as calculated<br />

in step 1 above)<br />

TCPP ¼ 5 10 4 particles=L 6; 070 L;<br />

TCCP ¼ 3:04 10 8 particles:<br />

Step 4: Determine the challenge particulate stock solution concentration using Eq. (7).<br />

Css ¼ TCPP=Vss; From ð7Þ (7Þ<br />

where TCPP = 3.04 10 8 particles (as calculated in step 3 above), Vss = ? (to be determined).<br />

Select a stock solution volume that is between 0.5 <strong>and</strong> 2% of the total test solution volume<br />

of 6,07 L (as determined in step 1 above). Thus:<br />

Vss = 100 L arbitrary selection<br />

Substituting values:<br />

ð0:005 6; 070LÞ

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