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Membrane and Desalination Technologies - TCE Moodle Website

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<strong>Membrane</strong> Separation: Basics <strong>and</strong> Applications 297<br />

Fig. 7.8. Calculating<br />

void space between<br />

spherical nodules.<br />

1. Calculate the area of the triangular void space.<br />

2. Calculate the radius of the circular pore whose cross-sectional area is equal to the triangular area<br />

calculated above.<br />

3. Subtract the thickness of the monolayer of water, 0.28 nm, which is adsorbed at the pore wall <strong>and</strong><br />

assumed to be immobile.<br />

4. Calculate the water flux using the relevant data in Example 7.1 <strong>and</strong> the following numerical<br />

values:<br />

np=Am ¼ 6:5 10 15 m 2 ;<br />

Dp ¼ 4:134 10 6 Pa;<br />

Dx ¼ 10 7 m;<br />

t ¼ 2:5;<br />

m ¼ 0:035 Pa s ðviscosity of water that fills nano-sized poresÞ:<br />

Answer<br />

1. Area of the triangular void space is 9:42 pffiffiffi<br />

ð 3 p=2Þ ¼14:25 nm2 2.<br />

pffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi<br />

The radius is 14:30=p ¼ 2:13 nm.<br />

.<br />

3. The effective radius of the mobile water channel is r ¼ 2:13 0:28 ¼ 1:85 nm:<br />

4. Water flux is<br />

J ¼ ð6:5 1015 Þð3:1416Þð1:85 10 9 Þ 4 ð4:134 10 6 Þ<br />

ð8Þð3:5 10 2 Þð2:5Þð10 7 Þ<br />

¼ 141:26 10 7 m 3 =m 2 s:<br />

Assuming water density of 10 3 kg/m 3 , the water flux is 141.26 10 -4 kg/m 2 s.<br />

6. MEMBRANE MODULE AND PROCESS DESIGN<br />

6.1. Introduction<br />

d = 18.8 nm<br />

Void<br />

space<br />

Spherical<br />

nodules<br />

As we know, large surface areas are required for industrial applications of membrane<br />

processes. A practical solution for providing this large surface area is packing the membranes

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