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popper-logic-scientific-discovery

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326<br />

new appendices<br />

(3) It will be applicable, with slight modifications, whenever we<br />

can assign a weight function to the various possibilities.<br />

(4) It will be applicable, or it will be of heuristic value, in most<br />

cases where an over-simplified estimate that works with equal possibilities<br />

leads to a solution approaching to the probabilities zero or one.<br />

(5) It will be of great heuristic value in cases in which weights can<br />

be introduced in the form of probabilities. Take, for example, the following<br />

simple problem: we are to calculate the probability of throwing<br />

with a die an even number when the throws of the number six are not<br />

counted, but considered as ‘no throw’. The classical definition leads, of course,<br />

to 2/5. We may now assume that the die is biased, and that the<br />

(unequal) probabilities p(1), p(2), . . . , p(6) of its sides are given. We<br />

can then still calculate the required probability as equal to<br />

p(2) + p(4)<br />

p(1) + p(2) + p(3) + p(4) + p(5)<br />

= p(2) + p(4)<br />

1 − p(6)<br />

That is to say, we can modify the classical definition so as to yield the<br />

following simple rule:<br />

Given the probabilities of all the (mutually exclusive) possible cases,<br />

the required probability is the sum of the probabilities of all the<br />

(mutually exclusive) favourable cases, divided by the sum of the<br />

probabilities of all the (mutually exclusive) possible cases.<br />

It is clear that we can also express this rule, for exclusive or<br />

non-exclusive cases, as follows.<br />

The required probability is always equal to the probability of the<br />

disjunction of all the (exclusive or non-exclusive) favourable cases,<br />

divided by the probability of the disjunction of all the (exclusive or<br />

non-exclusive) possible cases.<br />

(6) These rules can be used for a heuristic derivation of the definition<br />

of relative probability, and of the general multiplication theorem.<br />

For let us symbolize, in the last example, ‘even’ by ‘a’ and ‘other than<br />

a six’ by ‘b’. Then our problem of determining the probability of an<br />

even throw if we disregard throws of a six is clearly the same as the<br />

problem of determining p(a, b), that is to say, the probability of a, given<br />

b, or the probability of finding an a among the b’s.<br />

The calculation can then proceed as follows. Instead of writing

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