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362<br />

new appendices<br />

form: it is unconditional and free of the unusual ‘ + p(c¯, c)’. (79) can be<br />

further generalized:<br />

(80) p(b¯c¯, ad) = p(b, ad) + p(c, ad) − p(bc, ad) 79<br />

(81) p(a b¯c¯, d) = p(ab, d) + p(ac, d) − p(a(bc), d) 80, B2, 40<br />

This is a generalization of (79).<br />

We now proceed to the derivation of the law of distribution. It may<br />

be obtained from (79), (81), and a simple lemma (84) which I propose<br />

to call the ‘distribution lemma’, and which is a generalization of<br />

(30):<br />

(82) p(a(bc), d) = p(a, (bc)d)p(bc, d) = p((aa)(bc),d) B2, 30<br />

(83) p(((aa)b)c, d) = p(a(ab), cd)p(c, d) = p(((ab)a)c, d) B2, 62, 40<br />

(84) p(a(bc), d) = p((ab)(ac), d) 82, 83, 62<br />

This is the ‘distribution lemma’.<br />

(85) p(ab ac, d) = p(ab, d) + p(ac, d) − p((ab)(ac), d) 79 (subst.)<br />

To this formula and (81) we can now apply the ‘distribution lemma’;<br />

and we obtain:<br />

(86) p(a b¯c¯, d) = p(ab ac, d) 81, 85, 84<br />

This is a form of the first law of distribution. It can be applied to the<br />

left side of the following formula<br />

(87) p(b¯b¯a, c) = p(b¯b¯, ac)p(a, c) = p(a, c) B2, 74<br />

We then obtain,<br />

(88) p(ab ab¯, c) = p(a, c). 86, 87, 40<br />

It may be noted that<br />

(89) p(ā¯b, c) = p(ab, c), 68 (subst.)

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